Find the vale of P(X= 1): The value of P(X= 1) is obtained as given below: P(X =1)= P(X<1) – P(X <0) = F(1)– F(0) 6 2 7 7 4 Find the value of P(0 < X<2): The value of P(0 < X< 2) is obtained as given below: P(0
Find the vale of P(X= 1): The value of P(X= 1) is obtained as given below: P(X =1)= P(X<1) – P(X <0) = F(1)– F(0) 6 2 7 7 4 Find the value of P(0 < X<2): The value of P(0 < X< 2) is obtained as given below: P(0
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
Construct cumulative distribution function on the said picture below
Transcribed Image Text:Cumulative distribution function:
The cumulative distribution function F(x) is
obtained as given below:
F(x)= P(X <x)
;x<0
f(0)
;0Sx<1
f(0)+ f(1)
;1<x<2
(F(0)+ f(1)+ ƒ (2) ;1<x<2
;x<0
;0Sx<1
={2 4
;1<x<2
7'7
2 4 1
+-+-
l7'7'7
;2<x
;x<0
;0<x<1
;15x<2
7
1 ;2<x
Transcribed Image Text:Step2
b)
Find the vale of P(X= 1):
The value of P(X= 1) is obtained as given
below:
P(X =1)= P(X <1) – P(X <0)
= F(1)– F(0)
%3D
6 2
7
7
4
7
Find the value of P(0 < X< 2):
The value of P(0 < X < 2) is obtained as
given below:
P(0<X<2)= P(X <2) – P(X<0)
= F(2)– F(0)
2
=1-
7
5
7
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