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A company manufactures electric light bulbs whose lifetime is normally distributed with a mean of 800 hours and a standard deviation of 40 hours. If a random sample of 30 light bulbs yields an average life time of only 788 hours. Test the hypothesis that u=800 hours versus the alternative uz 800 hours. By using a significance level of 4%, it can be concluded that 1. O Z= -1.64 and accept H0 2. O: Z= -2.64 and accept H0 3. O Z= -2.64 and reject HO 4. O Z= -1.64 and reject HO

A company manufactures electric light bulbs whose lifetime is normally distributed with a mean of 800 hours and a standard deviation of 40 hours. If a random sample of 30 light bulbs yields an average life time of only 788 hours. Test the hypothesis that u=800 hours versus the alternative uz 800 hours. By using a significance level of 4%, it can be concluded that 1. O Z= -1.64 and accept H0 2. O: Z= -2.64 and accept H0 3. O Z= -2.64 and reject HO 4. O Z= -1.64 and reject HO

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A company manufactures electric light bulbs whose lifetime is normally distributed with a mean of 800 hours and a standard deviation of 40 hours. If a random sample of 30 light bulbs yields an average life time of only 788 hours. Test the hypothesis that u=800 hours versus the alternative uz 800 hours. By using a significance level of 4%, it can be concluded that 1. O Z= -1.64 and accept H0 2. O: Z= -2.64 and accept H0 3. O Z= -2.64 and reject HO 4. O Z= -1.64 and reject HO
Transcribed Image Text:A company manufactures electric light bulbs whose lifetime is normally distributed with a mean of 800 hours and a standard deviation of 40 hours. If a random sample of 30 light bulbs yields an average life time of only 788 hours. Test the hypothesis that u=800 hours versus the alternative uz 800 hours. By using a significance level of 4%, it can be concluded that 1. O Z= -1.64 and accept H0 2. O: Z= -2.64 and accept H0 3. O Z= -2.64 and reject HO 4. O Z= -1.64 and reject HO
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