A company has $7,730 available per month for advertising. Newspaper ads cost $120 each and can't run more than 18 times per month. Radio ads cost $510 each and can't run more than 26 times per month at this price. Each newspaper ad reaches 6950 potential customers, and each radio ad reaches 8450 potential customers. The company wants to maximize the number of ad exposures to potential customers. Use n for number of Newspaper advertisements and r for number of Radio advertisements. Maximize P = 18 ≤26 subject to ≤ $7,730 Enter the solution below. If needed, round ads to 1 decimal palace and group exposure to the nearest whole person. Number of Newspaper ads to run is Number of Radio ads to run is Maximum target group exposure is people
A company has $7,730 available per month for advertising. Newspaper ads cost $120 each and can't run more than 18 times per month. Radio ads cost $510 each and can't run more than 26 times per month at this price. Each newspaper ad reaches 6950 potential customers, and each radio ad reaches 8450 potential customers. The company wants to maximize the number of ad exposures to potential customers. Use n for number of Newspaper advertisements and r for number of Radio advertisements. Maximize P = 18 ≤26 subject to ≤ $7,730 Enter the solution below. If needed, round ads to 1 decimal palace and group exposure to the nearest whole person. Number of Newspaper ads to run is Number of Radio ads to run is Maximum target group exposure is people
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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