A company claims that each batch of its deluxe mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8% Brazil nuts. To test this claim, a quality-control inspector takes a random sample of 150 nuts from the latest batch. The table displays the sample data. Type of nut Cashew Almond Macadamia Brazil Count 83 29 20 18 The inspector has also calculated the expected counts for each type of nut: Cashew = 78, Almond = 40.5, Macadamia = 19.5, Brazil = 12. Using a calculator, the inspector found a x² statistic of 6.599 and a P-value of 0.0858.. What conclusion would you draw about the company's claimed distribution for its deluxe mixed nuts? Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because the P-value of 0.0858> 0.05, we fail to reject Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because x² = 6.599 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because the P-value of 0.0858 > 0.05, we accept Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is correct. Because the P-value of 0.0858 > 0.05, we reject Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question
A company claims that each batch of its deluxe mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8%
Brazil nuts. To test this claim, a quality-control inspector takes a random sample of 150 nuts from the latest batch. The table
displays the sample data.
Type of nut Cashew Almond Macadamia Brazil
Count
83
29
20
18
The inspector has also calculated the expected counts for each type of nut: Cashew = 78, Almond = 40.5, Macadamia = 19.5,
Brazil = 12. Using a calculator, the inspector found a x² statistic of 6.599 and a P-value of 0.0858..
What conclusion would you draw about the company's claimed distribution for its deluxe mixed nuts?
Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's
claimed distribution for its deluxe mixed nuts is not correct.
Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do have convincing evidence that the company's
claimed distribution for its deluxe mixed nuts is not correct.
2
Because x² = 6.599 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed
distribution for its deluxe mixed nuts is not correct.
Because the P-value of 0.0858 > 0.05, we accept
distribution for its deluxe mixed nuts is correct.
Because the P-value of 0.0858 > 0.05, we reject Ho. We do have convincing evidence that the company's claimed
distribution for its deluxe mixed nuts is not correct.
We do have convincing evidence that the company's claimed
Transcribed Image Text:A company claims that each batch of its deluxe mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8% Brazil nuts. To test this claim, a quality-control inspector takes a random sample of 150 nuts from the latest batch. The table displays the sample data. Type of nut Cashew Almond Macadamia Brazil Count 83 29 20 18 The inspector has also calculated the expected counts for each type of nut: Cashew = 78, Almond = 40.5, Macadamia = 19.5, Brazil = 12. Using a calculator, the inspector found a x² statistic of 6.599 and a P-value of 0.0858.. What conclusion would you draw about the company's claimed distribution for its deluxe mixed nuts? Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. 2 Because x² = 6.599 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because the P-value of 0.0858 > 0.05, we accept distribution for its deluxe mixed nuts is correct. Because the P-value of 0.0858 > 0.05, we reject Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. We do have convincing evidence that the company's claimed
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Similar questions
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman