A company claims that each batch of its deluxe mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8% Brazil nuts. To test this claim, a quality-control inspector takes a random sample of 150 nuts from the latest batch. The table displays the sample data. Type of nut Cashew Almond Macadamia Brazil Count 83 29 20 18 The inspector has also calculated the expected counts for each type of nut: Cashew = 78, Almond = 40.5, Macadamia = 19.5, Brazil = 12. Using a calculator, the inspector found a x² statistic of 6.599 and a P-value of 0.0858.. What conclusion would you draw about the company's claimed distribution for its deluxe mixed nuts? Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because the P-value of 0.0858> 0.05, we fail to reject Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because x² = 6.599 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because the P-value of 0.0858 > 0.05, we accept Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is correct. Because the P-value of 0.0858 > 0.05, we reject Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct.

MATLAB: An Introduction with Applications
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A company claims that each batch of its deluxe mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8%
Brazil nuts. To test this claim, a quality-control inspector takes a random sample of 150 nuts from the latest batch. The table
displays the sample data.
Type of nut Cashew Almond Macadamia Brazil
Count
83
29
20
18
The inspector has also calculated the expected counts for each type of nut: Cashew = 78, Almond = 40.5, Macadamia = 19.5,
Brazil = 12. Using a calculator, the inspector found a x² statistic of 6.599 and a P-value of 0.0858..
What conclusion would you draw about the company's claimed distribution for its deluxe mixed nuts?
Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's
claimed distribution for its deluxe mixed nuts is not correct.
Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do have convincing evidence that the company's
claimed distribution for its deluxe mixed nuts is not correct.
2
Because x² = 6.599 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed
distribution for its deluxe mixed nuts is not correct.
Because the P-value of 0.0858 > 0.05, we accept
distribution for its deluxe mixed nuts is correct.
Because the P-value of 0.0858 > 0.05, we reject Ho. We do have convincing evidence that the company's claimed
distribution for its deluxe mixed nuts is not correct.
We do have convincing evidence that the company's claimed
Transcribed Image Text:A company claims that each batch of its deluxe mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8% Brazil nuts. To test this claim, a quality-control inspector takes a random sample of 150 nuts from the latest batch. The table displays the sample data. Type of nut Cashew Almond Macadamia Brazil Count 83 29 20 18 The inspector has also calculated the expected counts for each type of nut: Cashew = 78, Almond = 40.5, Macadamia = 19.5, Brazil = 12. Using a calculator, the inspector found a x² statistic of 6.599 and a P-value of 0.0858.. What conclusion would you draw about the company's claimed distribution for its deluxe mixed nuts? Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because the P-value of 0.0858 > 0.05, we fail to reject Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. 2 Because x² = 6.599 > 0.05, we fail to reject Ho. We do not have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. Because the P-value of 0.0858 > 0.05, we accept distribution for its deluxe mixed nuts is correct. Because the P-value of 0.0858 > 0.05, we reject Ho. We do have convincing evidence that the company's claimed distribution for its deluxe mixed nuts is not correct. We do have convincing evidence that the company's claimed
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