A company advertises two car tire models. The number of thousands of miles that the standard model tires last has a mean \mu_S = 60μS=60 and standard deviation \sigma_S = 5σS=5. The number of miles that the extended life tires last has a mean \mu_E = 70μE=70 and standard deviation \sigma_E = 7σE=7. If mileages for both tires follow a normal distribution, what is the probability that a randomly selected standard model tire will get more mileage than a randomly selected extended life tire? (A) 0.108 (B) 0.123 (C) 0.434 (D) 0.566 (E) 0.592
A company advertises two car tire models. The number of thousands of miles that the standard model tires last has a mean \mu_S = 60μS=60 and standard deviation \sigma_S = 5σS=5. The number of miles that the extended life tires last has a mean \mu_E = 70μE=70 and standard deviation \sigma_E = 7σE=7. If mileages for both tires follow a normal distribution, what is the probability that a randomly selected standard model tire will get more mileage than a randomly selected extended life tire? (A) 0.108 (B) 0.123 (C) 0.434 (D) 0.566 (E) 0.592
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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6. A company advertises two car tire models. The number of thousands of miles that the standard model tires last has a mean \mu_S = 60μS=60 and standard deviation \sigma_S = 5σS=5. The number of miles that the extended life tires last has a mean \mu_E = 70μE=70 and standard deviation \sigma_E = 7σE=7. If mileages for both tires follow a normal distribution , what is the probability that a randomly selected standard model tire will get more mileage than a randomly selected extended life tire?
- (A) 0.108
- (B) 0.123
- (C) 0.434
- (D) 0.566
- (E) 0.592
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