A collection of charged particles moves with a uniform velocity = 42(m/s). The region has uniform electric field E= 20ỳ (V/m) and uniform magnetic field B=bo (Wb/m²). Charged particles O O F₁ = QE O OB F-Qu X B Aperture Particles with constant velocity An important principle is that , E and B are mutually perpendicular so that the electric force and magnetic force cancel with each other.
A collection of charged particles moves with a uniform velocity = 42(m/s). The region has uniform electric field E= 20ỳ (V/m) and uniform magnetic field B=bo (Wb/m²). Charged particles O O F₁ = QE O OB F-Qu X B Aperture Particles with constant velocity An important principle is that , E and B are mutually perpendicular so that the electric force and magnetic force cancel with each other.
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Hundred percent efficiency needed in the order to get positive feedback please show me neat and clean solution for it by hand solution needed
Please solve with hundred percent efficiency
Transcribed Image Text:A collection of charged particles moves with a uniform velocity = 42(m/s). The region has uniform electric field E= 20ŷ(V/m) and uniform magnetic
field B-bo (Wb/m²).
Charged
particles
AF, = QE
O O
O
B
E
Fm Qu X B
Aperture
Particles with
constant velocity
An important principle is that , E and B are mutually perpendicular so that the electric force and magnetic force cancel with each other.
Please reply to this thread on bo? such that the particle will maintain the constant velocity without any deflection. Discuss whether the velocity filter works for
both positively charged and negatively charged particles. When the particles have different values in their mass but maintain the same speed, would they
behave the same passing the aperture in the design above?
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