A coil of 15 turns and radius 10.0 cm surrounds a long solenoid of radius 1.80 cm and 1.00 x 10 turns/meter (see figure below). The current in the solenoid changes as I = 2.00 sin 120 t, where I is in amperes and t is in seconds. Find the induced emf (in volts) in the 15-turn coil as a function of time. 15-turn coil
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Q: induced emf (in volts) in the 15-turn coil as a function of time.
A: We know that, ε=-dϕdt......Faraday's lawwhere, ϕ is magnetic flux ε is induced emfThis law gives us…
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A: Induced emf ε=-Ndϕdt=-NddtBA=-Nddtμ0nIA=-Nμ0nAdIdt=-Nμ0nAddt7.00sin120t=-154π×10-7 Hm1.00×103…
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A: Given:- N =450 turns I = 34(1- e-1.60t ) R=6cm = 0.06 m n = 250 turns
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- A solenoid of lenght 40 cm has 360 turns of radius 2.8 cm. A tightly wound coil with 8 turns of radius 6 cm is placed around the solenoid. The axes of the coil and solenoid coincide. Find the emf induced in the coil if the current in the solenoid varies according to I = 6sin(120Tt) A. -6.301 cos(120Tt) mVA long solenoid has n = 420 turns per meter and carries a current given by I 33.0(1 – e-1.60t 60t ), where I is in amperes and t is in seconds. Inside the solenoid and coaxial with it is a coil that has a radius of R = 6.00 cm and consists of a total of N = 250 turns of fine wire (see figure below). What emf is induced in the coil by the changing current? (Use the following as necessary: t. Assume E is in mV and t is in seconds.) E = -.078e-1.60t I n turns/m ©0000000000 R 000000000000000000000 N turnsA coil of 15 turns and radius 10.0 cm surrounds a long solenoid of radius 1.60 cm and 1.00 x 10° turns/meter (see figure below). The current in the solenoid changes as I = 6.00 sin 120 t, where I is in amperes and t is in seconds. Find the induced emf (in volts) in the 15-turn coil as a function of time. E = 15-turn coil
- A coil of 15 turns and radius 10.0 cm surrounds a long solenoid of radius 2.40 cm and 1.00*103 turns/meter (see figure below). The current in the solenoid changes as I = 7.00 sin 120 t, where I is in amperes and t is in seconds. Find the induced emf (in volts) in the 15-turn coil as a function of timeAn inductor with L = 2.5 H is in a closed circuit with I= 0.45 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.18 s. L = 2.5 H I= 0.45 A At = 0.18 s (a) Express the magnitude of the average induced emf on the inductor, &are, in terms of L, I and At. IA coil of Nc =40 turns and radius 0.5 m surrounds a long solenoid of radius 0.1 m and n=800 turns per meter in Figure. The current in the solenoid changes as ?0 = 4? −3? . (a) Find the induced emf in the coil as a function of time. (b) Find the mutual-inductance of solenoid.
- Don't use chat gpt Chatgpt means downvoteA toroidal solenoid has 800 turns, cross-sectional area of 16.25 cm^2, and an average radius of 14.00 cm.a) Calculate the self-inductance of the coil.b) If the current decreases uniformly from 15.00 A to 12.00 A In 3.00 ms, calculate the self-induced electromotive force in the coil.c) Current is directed from terminal a of the coil to terminal b. Is the direction of the induced electromotive force from a to b, or from b to a? Why?4. A coil of 15 turns and radius 10 cm surrounds a long solenoid of radius 2.00 cm and has 1.00 x 103 turns per meter. The current in the solenoid changes as I = 5.00 sin 120t, where I is in amps and t is in seconds. Find the induced emf in the 15 turn coil as a function of time. %3D