A coil 4.20 cm radius, containing 420 turns, is placed in a uniform magnetic field that varies with time according to B=(1.20×10 2T/s)+( 2.70x10-5 T/s). The coil is connected to a 700- 2 resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil. ↓ Y Part A Find the magnitude of the induced emf in the coil as a function of time. 8.89-10-³ V +(8.00×105 V/s³ )³ E 279x102V +(6.28×105 V/s³ )³ E=2.79×102 V +(2.51*10-4V/s³ )³ E-8.89-10³ V +(2.51*10-4 V/s³ )3 Submit Previous Answers Correct Part B What is the current in the resistor at time to = 4.95 s? VE ΑΣΦ 1= 4.16 10 5 Submit Previous Answers Request Answer X Incorrect; Try Again ? A
A coil 4.20 cm radius, containing 420 turns, is placed in a uniform magnetic field that varies with time according to B=(1.20×10 2T/s)+( 2.70x10-5 T/s). The coil is connected to a 700- 2 resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil. ↓ Y Part A Find the magnitude of the induced emf in the coil as a function of time. 8.89-10-³ V +(8.00×105 V/s³ )³ E 279x102V +(6.28×105 V/s³ )³ E=2.79×102 V +(2.51*10-4V/s³ )³ E-8.89-10³ V +(2.51*10-4 V/s³ )3 Submit Previous Answers Correct Part B What is the current in the resistor at time to = 4.95 s? VE ΑΣΦ 1= 4.16 10 5 Submit Previous Answers Request Answer X Incorrect; Try Again ? A
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![A coil 4.20 cm radius, containing 420 turns, is
placed in a uniform magnetic field that varies with
time according to B=( 1.20x10-2 T/s)t+(
2.70x10-5 T/s). The coil is connected to a 700-
2 resistor, and its plane is perpendicular to the
magnetic field. You can ignore the resistance of the
coil.
↓
▼
Part A
Find the magnitude of the induced emf in the coil as a function of time.
8.89×10³ V +(8.00-10-5 V/s³ )³
ⒸE=2.79×10 2 V +(6.28×10-5 V/s³ )t³
E = 2.79×10² V +(2.51×10-4 V/s³ )t³
£ 8.89-10 ³ V +(2.51×10 4 V/s³ )t3
Submit
Previous Answers
✓ Correct
Part B
What is the current in the resistor at time to = 4.95s ?
ΑΣΦ
1= 4.16 107
Submit Previous Answers Request Answer
X Incorrect; Try Again
A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F00e5c5de-298c-41fb-9861-0262471f9c17%2F533d0e51-8302-488f-b3d0-a7ceb152f57d%2Fyqhqt8s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A coil 4.20 cm radius, containing 420 turns, is
placed in a uniform magnetic field that varies with
time according to B=( 1.20x10-2 T/s)t+(
2.70x10-5 T/s). The coil is connected to a 700-
2 resistor, and its plane is perpendicular to the
magnetic field. You can ignore the resistance of the
coil.
↓
▼
Part A
Find the magnitude of the induced emf in the coil as a function of time.
8.89×10³ V +(8.00-10-5 V/s³ )³
ⒸE=2.79×10 2 V +(6.28×10-5 V/s³ )t³
E = 2.79×10² V +(2.51×10-4 V/s³ )t³
£ 8.89-10 ³ V +(2.51×10 4 V/s³ )t3
Submit
Previous Answers
✓ Correct
Part B
What is the current in the resistor at time to = 4.95s ?
ΑΣΦ
1= 4.16 107
Submit Previous Answers Request Answer
X Incorrect; Try Again
A
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