A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. The mean wake time of 44 subjects using the drug was 94 min. Assume that the population is normally distributed with a standard deviation of 18 min. Construct a 99% confidence interval estimate of the mean. What is the lower bound of the confidence interval? What is the margin of error? If the average wake time of untreated subjects is 100 minutes, does the drug appear to be effective?
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: From the provided information: Sample size, n=43. Sample mean, x¯=3.4. Sample standard deviation,…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: The random variable LDL cholesterol level follows normal distribution. We have to construct 99%…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A: Given information- Sample size, n = 48 Sample mean, x-bar = 3.4 Sample standard deviation, s = 18.9…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: Given that Sample size =44 subjects Mean difference=3.4 Sample standard deviation (before-after)…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
A: From the provided information, Sample size (n) = 50 Sample mean (x̄) = 2.8 Standard deviation (s) =…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A: We have given that, The given information is -The sample mean change in the LDL cholesterol level…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: The sample size is 44, the mean is 4.9 and the standard deviation is 15.7.
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: Given Information: Sample size n=43 Sample mean x¯d=3.2 Sample standard deviation sd=17.9 Confidence…
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A: Givensample size(n)=49Mean(x)=0.8004standard deviation(sx)=0.0782confidence level=90%
Q: In a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with…
A: Let d denotes the changes (before-after) in the levels of LDL cholesterol (in mg/dL) of the…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: From the provided information, Sample size (n) = 42 Sample mean (x̄) = 3.5 Sample standard deviation…
Q: a. What is the best point estimate of the population mean net change in LDL cholesterol after the…
A: From the provided information, Sample size (n) = 43 Sample mean (x̄) = 3.7 Sample standard deviation…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
A: Given n=50 Mean=5.5 Standard deviations=17.9 Alpha=0.01
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A: Given that x¯=5.2s=15.6n=48 Confidence level=90% Significance level=1-0.90=0.10 degrees of freedom,…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: given data sample size (n) = 43sample mean ( x¯ ) = 4.2sample standard deviatio (s) =17.890% ci for…
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A: Given that: Population mean, μ=215.60 n = 64 x¯=252.45 s = 74.50
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: Sample mean = x̅ = 4.5 Sample size = n = 43 Sample S.D = s = 16.8 Standard Error = s/√n =…
Q: In a test of the effectiveness of garlic for lowvering cholesterol, 45 subjects were treated with…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: From the provided information, Sample size (n) = 42 Sample mean (x̄) = 4.4 Sample standard deviation…
Q: Is smoking during pregnancy associated with premature births? To investigate this question,…
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Q: clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Sample size : n=25 Before treatment , Sample mean : x¯1=103 After treatment , Sample mean : x¯2=96.1…
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A: According to the information provided Sample size n=10 sample mean=50 The sample standard deviation…
Q: What does the confidence interval suggest about the effectiveness of garlic in reducing LDL…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A: Suppose defines the true population mean net change in LDL cholesterol after the garlic treatment.
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with…
A: Given that, x¯=2.9,s=19.1,n=45 The degree of freedom is, df =n-1 =45-1 =44 Critical value:…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A: Given: Number of subjects or sample size (n) = 48 Mean of the changes d¯=2.8 Standard deviation of…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: It is given that sample mean is 2.7 and standard deviation is 18.9.
Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
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Q: wat distribution tal W. Rage 1 of the sta w Rage 2 of the sta fidence interval estim
A: According to the sum, in a test of the effectiveness of garlic for lowering cholesterol, 43 objects…
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A: It is given that sample mean is 252.45 and the standard deviation is 74.50.
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: From the provided information, Sample size (n) = 43 Sample mean (x̄) = 3.1 Sample standard deviation…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: Given : Sample Size, n = 42 Sample Mean, x̄ = 5.7 sample standard…
A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. The
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What is the margin of error?
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- In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.1 and a standard deviation of 16.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL <µIn a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.1 and a standard deviation of 19.1. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? O mg/dL < µWe have developed a new drug used to reduce fever and want to test its efficacy. Ten ER patients who are running a fever agree to take the new drug instead of the traditional treatment. Their temperatures are taken before the drug is administered and 30 minutes after taking the drug. The results are recorded in the Excel file below. Use the data to construct and interpret a 99% confidence interval for the mean change in temperatures of patients after taking this drug using Excel. Be sure to include any explanation necessary along with a sentence that explains what the interval means. First Temp Second Temp 100.1 98.9 101.3 99.1 102.1 99.2 102.7 99 101.9 98.7 100.8 98.6 103.1 99.4 102.5 99.2 103.5 100.1 101.7 99.2In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.5 and a standard deviation of 19.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? O mg/dL < µIn a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.9 and a standard deviation of 15.3. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? | mg/dL < µIn a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.6 and a standard deviation of 17.5. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL <µ< mg/dL (Round to two decimal places as needed.)A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 20 subjects had a mean wake time of 105.0 min. After treatment, the 20 subjects had a mean wake time of 82.5 min and a standard deviation of 22.5 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment. ???? min<μ<???? minIn a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 2.0 and a standard deviation of 16.5. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?In a study of the use of hypnosis to relieve pain, sensory ratings were measured for 8 subjects and the mean sensory ratings was found to be 2.8 and standard deviation to be 0.3. The sensory ratings are normally distributed. The 80% confidence interval for the mean sensory ratings of the population is (9.35,11.65) b. (3.58, 4.64) (2.65, 2.95) d. (3.09, 3.91) (6.27, 8.73) a. C. e.In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.1 and a standard deviation of 19.1. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL < µIn a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.7 and a standard deviation of 18.2. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean p? Question Viewer mg/dL < p< mg/dL (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits do not…In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before- after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.1 and a standard deviation of 15.8. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? mg/dL mg/dL<µ< (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits contain 0, suggesting that the…SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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