A clay specimen drained on both sides was tested. The data were obtained P1=50 kPa e1=0.92 P2=120 kPa e2=0.78 Time for 50% consolidation=2.5 min Tv=0.197 Determine the following 1. Coefficient of compressibility (Ans. 1.08x10-3 m2/kN)

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Q: Results of a laboratory consolidation test on a 10 meter thick clay indicates t 50 = 12.5 minutes…

A: given data:- thickness of lab sample=3.18 cm time taken by sample to get 50% consolidation=12.5…

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Q: Given that B =1 m, L = 3 m, and Q = 110 kN, the soil characteristics given in the figure are Cs =…

A: Given - Given that B =1 m, L = 3 m, and Q = 110 kN, the soil characteristics given in the figure are…

Q: a. Determine the coefficient of consolidation for the load range in cm squared/min. b. Based on the…

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Q: In a consolidation test, when the load is changed from 50 kN/m² to 100 kN/m², then the void ratio…

A: Given data,  Initial stress (σ0') = 50 kN/m² Final stress (σ'1) = 100 kN/m² e1 = 0.8 e2 = 0.6   To…

Q: Please provide solution for this consolidation test quest

A: P1 is equal to 50 KpaP2 is equal to 120 Kpae1 is equal to .92e2 is equal to 0.78Time required for…

Q: Two identically clay samples of the same size designated as A and B are subjected to consolidation…

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Consolidation parameters

Consolidation is the process of expulsion of pore water present in the voids of soil solids under the pressure of the applied load. This is a quick process in the case of coarse-grained soils since the permeability is high due to the presence of more voids, while it is a slow and gradual process in the case of clayey soil as the permeability of clay is less. An example of consolidation is the settlement of soil under a building due to the load coming from the building.