Results of a laboratory consolidation test on a 10 meter thick clay indicates t 50 = 12.5 minutes for the load increment of 10 tons/sq ft. The lab sample had drainage on top and on the bottom. The lab sample height is 3.18 cm. a. Determine the coefficient of consolidation for the load range in cm squared/min. b. Based on the laboratory results above (a), compute the time it will take for 100 % consolidation of the 10 meter thick clay layer in the field. A sand layer overlies the clay layer and impervious rock underlies the clay layer. Answer the time in years.

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Results of a laboratory consolidation test on a 10 meter thick clay indicates
t 50 = 12.5 minutes for the load increment of 10 tons/sq ft. The lab sample
had drainage on top and on the bottom. The lab sample height is 3.18 cm.
a. Determine the coefficient of consolidation for the load range in cm
squared/min.
b. Based on the laboratory results above (a), compute the time it will
take for 100 % consolidation of the 10 meter thick clay layer in the
field. A sand layer overlies the clay layer and impervious rock
underlies the clay layer. Answer the time in years.
Transcribed Image Text:Results of a laboratory consolidation test on a 10 meter thick clay indicates t 50 = 12.5 minutes for the load increment of 10 tons/sq ft. The lab sample had drainage on top and on the bottom. The lab sample height is 3.18 cm. a. Determine the coefficient of consolidation for the load range in cm squared/min. b. Based on the laboratory results above (a), compute the time it will take for 100 % consolidation of the 10 meter thick clay layer in the field. A sand layer overlies the clay layer and impervious rock underlies the clay layer. Answer the time in years.
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