A circular shaft has a diameter d [m] that varies with axial position x [m] according to d = 0.02(1/x²)/e*;0
A circular shaft has a diameter d [m] that varies with axial position x [m] according to d = 0.02(1/x²)/e*;0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
1. SIMPSON’S 1/3 RULE (? → ? + 2ℎ)
2. PRECISE RULE (? → ? + 4ℎ)
3. % R. E. = [(PRECISE RULE−SIMPSON′S RULE)/PRECISE RULE]× 100
![A circular shaft has a diameter d [m] that varies with axial position x [m]
I.
according to
d = 0.02(1/x²)/e*;0 < x < 3m
An axial load P of 30000 N is applied to one end of the shaft whose modulus
of elasticity E is 2 × 1011N/m². The axial elongation of the shaft is Ax [m]
and is given
Ax
(P / E) (1/ A)dx ; A = cross-sectional area = nd?/4
Estimate Ax by
1. SIMPSON'S RULE (a → a + 2h)
2. PRECISE RULE (a → a + 4h)
PRECISE RULE-SIMPSON'S RULE
3. % R. E. =
× 100
PRECISE RULE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F15ff4a29-91be-4ef0-87b1-c64551fe6c6d%2F4f529b1f-c35d-4e14-ac26-a4f8d1c52f4d%2Ft9uo8o_processed.png&w=3840&q=75)
Transcribed Image Text:A circular shaft has a diameter d [m] that varies with axial position x [m]
I.
according to
d = 0.02(1/x²)/e*;0 < x < 3m
An axial load P of 30000 N is applied to one end of the shaft whose modulus
of elasticity E is 2 × 1011N/m². The axial elongation of the shaft is Ax [m]
and is given
Ax
(P / E) (1/ A)dx ; A = cross-sectional area = nd?/4
Estimate Ax by
1. SIMPSON'S RULE (a → a + 2h)
2. PRECISE RULE (a → a + 4h)
PRECISE RULE-SIMPSON'S RULE
3. % R. E. =
× 100
PRECISE RULE
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