A circular rod 5 m long and 20 cm² in cross section is attached to a block of volume 0.025 m³ immersed in water and to a wall as shown in Fig.1. If the rod mass is 1.25 kg and makes an angle of 12 degrees to the horizontal at equilibrium. Find the mass of the block M. If the mass M is released from the rod, how much of the rod will remain submerged at equilibrium. (pw = 10³ kg/m³) 0.25 m 5m 10 = 12° Fig.1 ¥ = 0.025 m

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Q1:
A circular rod 5 m long and 20 cm? in cross section is attached to
a block of volume 0.025 m³ immersed in water and to a wall as
0.25 m
shown in Fig.1. If the rod mass is 1.25 kg and makes an angle of
12 degrees to the horizontal at equilibrium. Find the mass of the
block M. If the mass M is released from the rod, how much of the
rod will remain submerged at equilibrium.
(pw = 10³ kg/m³)
5m
10= 12
Fig.1
M -
¥ = 0.025 m³
E
Transcribed Image Text:Q1: A circular rod 5 m long and 20 cm? in cross section is attached to a block of volume 0.025 m³ immersed in water and to a wall as 0.25 m shown in Fig.1. If the rod mass is 1.25 kg and makes an angle of 12 degrees to the horizontal at equilibrium. Find the mass of the block M. If the mass M is released from the rod, how much of the rod will remain submerged at equilibrium. (pw = 10³ kg/m³) 5m 10= 12 Fig.1 M - ¥ = 0.025 m³ E
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