A circular ring with area 4.45 cm2 is carrying a current of 12.5 A. The ring, initially at rest, is immersed in a region of uniform magnetic field Find the rotational kinetic energy of the ring when it is in the second orientation. Express your answer with the appropriate units. given by B = (1.35 x 10-2 T)(122 + 33 – 4k). The ring is positioned initially such that its magnetic moment orientation is given by > View Available Hint(s) Kf = 8.86x10-4 J i = u(-0.8i + 0.6j), where u is the (positive) magnitude of the magnetic moment. Submit Previous Answers (a) Find the initial magnetic torque on the ring. (b) The ring (which is free to rotate around one diameter) is released and turns through an angle of 90.0°, at which point its magnetic moment orientation is given by i = -µk. Determine the decrease in potential energy. v Correct As expected for the object starting from the rest, the kinetic energy is equal to the change in potential energy with opposite sign. (c) If the moment of inertia of the ring about a diameter is 6.50 x 10-7 kg · m?, determine the angular speed of the ring as it passes through the second position. Part E EVALUATE Part F If the ring were free to rotate around any diameter, in what direction would the magnetic moment point when the ring is in a state of stable equilibrium? Enter the unit vector of that direction of the magnetic moment. Express your answer in terms of the unit vectors i, j, and k. v View Available Hint(s) Hint 1. Energy and Equilibrium The state of stable equilibrium is reached when potential energy is at a local minimum.

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A circular ring with area 4.45 cm² is carrying a
current of 12.5 A. The ring, initially at rest, is
immersed in a region of uniform magnetic field
Find the rotational kinetic energy of the ring when it is in the second orientation.
Express your answer with the appropriate units.
given by B = (1.35 x 10-2 T)(12i + 33 – 4k).
The ring is positioned initially such that its magnetic
moment orientation is given by
• View Available Hint(s)
= 8.86x10-4 J
i = µ(-0.8i + 0.6j), where µu is the (positive)
magnitude of the magnetic moment.
Submit
Previous Answers
(a) Find the initial magnetic torque on the ring.
(b) The ring (which is free to rotate around one
diameter) is released and turns through an angle of
90.0°, at which point its magnetic moment
orientation is given by i = -uk. Determine the
decrease in potential energy.
Correct
As expected for the object starting from the rest, the kinetic energy is equal to the change in
potential energy with opposite sign.
f
(c) If the moment of inertia of the ring about a
diameter is 6.50 × 10-7 kg · m², determine the
angular speed of the ring as it passes through the
second position.
Part E
EVALUATE
Part F
If the ring were free to rotate around any diameter, in what direction would the magnetic moment point
when the ring is in a state of stable equilibrium? Enter the unit vector of that direction of the magnetic
moment.
Express your answer in terms of the unit vectors i, j, and k.
View Available Hint(s)
Hint 1. Energy and Equilibrium
The state of stable equilibrium is reached when potential energy is at a local minimum.
ΑΣφ
?
Transcribed Image Text:A circular ring with area 4.45 cm² is carrying a current of 12.5 A. The ring, initially at rest, is immersed in a region of uniform magnetic field Find the rotational kinetic energy of the ring when it is in the second orientation. Express your answer with the appropriate units. given by B = (1.35 x 10-2 T)(12i + 33 – 4k). The ring is positioned initially such that its magnetic moment orientation is given by • View Available Hint(s) = 8.86x10-4 J i = µ(-0.8i + 0.6j), where µu is the (positive) magnitude of the magnetic moment. Submit Previous Answers (a) Find the initial magnetic torque on the ring. (b) The ring (which is free to rotate around one diameter) is released and turns through an angle of 90.0°, at which point its magnetic moment orientation is given by i = -uk. Determine the decrease in potential energy. Correct As expected for the object starting from the rest, the kinetic energy is equal to the change in potential energy with opposite sign. f (c) If the moment of inertia of the ring about a diameter is 6.50 × 10-7 kg · m², determine the angular speed of the ring as it passes through the second position. Part E EVALUATE Part F If the ring were free to rotate around any diameter, in what direction would the magnetic moment point when the ring is in a state of stable equilibrium? Enter the unit vector of that direction of the magnetic moment. Express your answer in terms of the unit vectors i, j, and k. View Available Hint(s) Hint 1. Energy and Equilibrium The state of stable equilibrium is reached when potential energy is at a local minimum. ΑΣφ ?
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