A circular object with a diameter of 5cm is rolling on a horizontal surface moving at 2m/s. It then rolls down an incline with a 30° angle below the horizontal, as it rolls down it takes 5.25 s at an constant acceleration of 1.2rad/s before setting on a second horizontal surface. What is the vertical height that the object travelled?

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Chapter1: Units, Trigonometry. And Vectors
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A circular object with a diameter of 5cm is rolling on a horizontal surface moving at 2m/s. It
then rolls down an incline with a 30° angle below the horizontal, as it rolls down it takes 5.25 s
at an constant acceleration of 1.2rad/s before setting on a second horizontal surface. What is
the vertical height that the object travelled?
Transcribed Image Text:A circular object with a diameter of 5cm is rolling on a horizontal surface moving at 2m/s. It then rolls down an incline with a 30° angle below the horizontal, as it rolls down it takes 5.25 s at an constant acceleration of 1.2rad/s before setting on a second horizontal surface. What is the vertical height that the object travelled?
Expert Solution
Step 1

Given data

The diameter of the circular object is d = 5 cm = 0.05 m

The linear velocity of the circular object is v = 2 m/s

The angle of inclination is θ = 30°

The time taken to roll down is t = 5.25 s

The radial acceleration of an object is α = 1.2 rad/s2

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