A circular loop of flexible iron wire has an initial circumference of 165.0 cm, but its circumference is decreasing at a constant rate of 12.0 cm/s due to a tangential pull on the wire. The loop is in a constant, uniform magnetic field oriented perpendicular to the plane of the loop of magnitude 0.500 T. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Generator iii: the slidewire generator. Part A Find the emf induced in the loop, at the instant when 9.00 s have passed. Express your answer in volts. E = ΕΠΙ ΑΣΦ ? V

A circular loop of flexible iron wire has an initial circumference of 165.0 cm, but its circumference is decreasing at a constant rate of 12.0 cm/s due to a tangential pull on the wire. The loop is in a constant, uniform magnetic field oriented perpendicular to the plane of the loop of magnitude 0.500 T. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Generator iii: the slidewire generator. Part A Find the emf induced in the loop, at the instant when 9.00 s have passed. Express your answer in volts. E = ΕΠΙ ΑΣΦ ? V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A circular loop of flexible iron wire has an initial circumference of 165.0 cm, but its circumference is decreasing at a constant rate of 12.0 cm/s due to a tangential pull on the wire. The loop is in a constant, uniform magnetic field oriented perpendicular to the plane of the loop of magnitude 0.500 T. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Generator iii: the slidewire generator. Part A Find the emf induced in the loop, at the instant when 9.00 s have passed. Express your answer in volts. E = 5.5x10-3 V Submit Previous Answers Answer Requested IDENTIFY and SET UP: Use Faraday's law to calculate the emf (magnitude and direction). The direction of the induced current is the same as the direction of the emf. The flux changes because the area of the loop is changing; relate dA/dt to dc/dt where c is the circumference of the loop. 2πr and A πr² so A = C²/4TT. EXECUTE: c = B = BA= (B/4π)c². B |e| = |dp| = (2) c|de|. dt Att = 9.0 s. c…
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