A chunk of iron at 90.6°C was added to 200.0 g of water at 15.5°C. The specific heat of iron is 0.449 J/g°C, and the specific heahof water is 4.184 J/g°C. The temperature of the resulting mixture was 18.2°C. Assuming no heat was lost to the surroundings, what was the mass of the iron added? 468 g A) B) C) 55.5 g 66.9 g 69.5 g D)
A chunk of iron at 90.6°C was added to 200.0 g of water at 15.5°C. The specific heat of iron is 0.449 J/g°C, and the specific heahof water is 4.184 J/g°C. The temperature of the resulting mixture was 18.2°C. Assuming no heat was lost to the surroundings, what was the mass of the iron added? 468 g A) B) C) 55.5 g 66.9 g 69.5 g D)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter6: Thermochemistry
Section: Chapter Questions
Problem 64E: A 110.-g sample of copper (specific heat capacity = 0.20 J/C g) is heated to 82.4C and then placed...
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![A chunk of iron at 90.6°C was added to 200.0 g of water at 15.5°C. The specific heat of iron is 0.449
J/g°C, and the specific heatof water is 4.184 J/g°C. The temperature of the resulting mixture was
18.2°C. Assuming no heat was lost to the surroundings, what was the mass of the iron added?
23.
468 g
A)
B)
55.5 g
66.9 g
69.5 g
D)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F11de35ad-8994-41a6-898f-1f496c017377%2F360d2fb8-1ce4-4383-8337-11b1024890e7%2Fr7oh7l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A chunk of iron at 90.6°C was added to 200.0 g of water at 15.5°C. The specific heat of iron is 0.449
J/g°C, and the specific heatof water is 4.184 J/g°C. The temperature of the resulting mixture was
18.2°C. Assuming no heat was lost to the surroundings, what was the mass of the iron added?
23.
468 g
A)
B)
55.5 g
66.9 g
69.5 g
D)
Expert Solution
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Step 1
Given: Mass of water = 200.0 g.
Initial temperature of water = 15.5 oC
Final temperature of mixture = 18.2 oC
Initial temperature of iron = 90.6 oC
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