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A chunk of iron at 90.6°C was added to 200.0 g of water at 15.5°C. The specific heat of iron is 0.449 J/g°C, and the specific heahof water is 4.184 J/g°C. The temperature of the resulting mixture was 18.2°C. Assuming no heat was lost to the surroundings, what was the mass of the iron added? 468 g A) B) C) 55.5 g 66.9 g 69.5 g D)

A chunk of iron at 90.6°C was added to 200.0 g of water at 15.5°C. The specific heat of iron is 0.449 J/g°C, and the specific heahof water is 4.184 J/g°C. The temperature of the resulting mixture was 18.2°C. Assuming no heat was lost to the surroundings, what was the mass of the iron added? 468 g A) B) C) 55.5 g 66.9 g 69.5 g D)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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A chunk of iron at 90.6°C was added to 200.0 g of water at 15.5°C. The specific heat of iron is 0.449 J/g°C, and the specific heatof water is 4.184 J/g°C. The temperature of the resulting mixture was 18.2°C. Assuming no heat was lost to the surroundings, what was the mass of the iron added? 23. 468 g A) B) 55.5 g 66.9 g 69.5 g D)
Transcribed Image Text:A chunk of iron at 90.6°C was added to 200.0 g of water at 15.5°C. The specific heat of iron is 0.449 J/g°C, and the specific heatof water is 4.184 J/g°C. The temperature of the resulting mixture was 18.2°C. Assuming no heat was lost to the surroundings, what was the mass of the iron added? 23. 468 g A) B) 55.5 g 66.9 g 69.5 g D)
Expert Solution
Step 1

Given: Mass of water = 200.0 g.

Initial temperature of water = 15.5 oC

Final temperature of mixture = 18.2 oC

Initial temperature of iron = 90.6 oC

 

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