A child starts from rest and slides without friction from a height of h = 5.0 m along a slide next to a pool (see fiqure). She is launched from a height of 0.8 m (ignore the h/5 in the fiqure) at an angle of 240 into the air over the pool Утах th/5 What is her maximum height above the water after leaving the slide? Hint: it is possible to do this without doing projectile motion, even desirable as we are trying to learn conservation of energy; this problem does require you to use conservation of energy more than once 3.1 Xm

A child starts from rest and slides without friction from a height of h = 5.0 m along a slide next to a pool (see fiqure). She is launched from a height of 0.8 m (ignore the h/5 in the fiqure) at an angle of 240 into the air over the pool Утах th/5 What is her maximum height above the water after leaving the slide? Hint: it is possible to do this without doing projectile motion, even desirable as we are trying to learn conservation of energy; this problem does require you to use conservation of energy more than once 3.1 Xm

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter3: Vectors And Two-Dimensional Motion

Section: Chapter Questions

Problem 8WUE: A catapult launches a large stone from ground level at a speed of 45.0 m/s at an angle of 55.0 with...

See similar textbooks

Related questions

Q: 10 m 3. A baseball player throws a 0.2 kg ball horizontally from the top of a 10 m tall hill with a…

A: According to the Newton's laws of motion , the final velocity of an object is calculated by using…

Q: DONT USE AI please, it can't answer this question correctly

Q: he highest barrier that a projectile can clear is 21.4 m, when the projectile is launched at an…

Q: Problem 2: During a baseball game, a baseball is struck at ground level by a batter. The ball leaves…

Q: A ski jumper starts from rest 47.5 m above the ground on a frictionless track and flies off the…

A: a) Velocity = 24.05 m/sb) maximum height above ground = 32.75 mc) She lands 59.02 m away from the…

Q: Problem 5: During a baseball game, a baseball is struck at ground level by a batter. The ball leaves…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: A friend of yours has a one story house with a pool in the backyard. Someone gets the bright idea to…

Q: a skateboarder moving at 5.90 m/s along a horizontal section of a track that is slanted upward by θ…

Q: Please determine the flight time of the racquet ball below.

Q: A golfer hits a shot to a green that is elevated 2.60 m above the point where the ball is struck.…

A: To determine the speed of a golf ball that assumes no air resistance and a constant gravitational…

Q: It's been a great day of new, frictionless snow. Julie starts at the top of the 60° slope with a…

Q: The same projectile experiment was conducted as you did in class. A racquet ball rolls down a track,…

A: Given Data: Height from which racquetball rolls down h=0.961 m The initial velocity of the ball…

Question

A child starts from rest and slides without friction from a height of h = 5.0 m along a slide next to a pool (see fiqure). She is launched from a height of 0.8 m (ignore the h/5 in the fiqure) at an angle of 240 into the air over the pool
Утах
th/5
What is her maximum height above the water after leaving the slide? Hint: it is possible to do this without doing projectile motion, even desirable as we are trying to learn conservation of energy; this problem does require you to use conservation of energy more than
once
3.1
Xm

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Trending now

This is a popular solution!

Step by step

Solved in 6 steps with 6 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Neglecting air resistance, how much would I have to raise the vertical height if I wanted to double the impact speed of a falling object?
If the net work done by external forces on a particle is zero, which of the following statements about the particle must be true? (a) Its velocity is zero. (b) Its velocity is decreased. (c) Its velocity is unchanged. (d) Its speed is unchanged. (e) More information is needed.
A bottle rocket is shot straight up in the air with a speed 30 m/s. if the air resistance is ignores, the bottle would go up to a height of approximately 46 m. however the rocket goes up to only 35 m before returning to the ground. What happened? Explain, giving only a qualitative response.
Pick an isolated system for the following scenarios while including the fewest number of objects as possible. a. A satellite in orbit around the Earth b. An airplane in flight c. A truck driving along the road d. A person jumping
A block of mass m is dropped from the fourth floor of an office building and hits the sidewalk below at speed v. From what floor should the mass be dropped to double that impact speed? (a) the sixth floor (b) the eighth floor (c) the tenth floor (d) the twelfth floor (e) the sixteenth floor
A student at the top of a building of height h throws one ball upward with a speed of i and then throws a second ball downward with the same initial speed i. Just before it reaches the ground, is the final speed of the ball thrown upward (a) larger, (b) smaller, or (c) the same in magnitude, compared with the final speed of the ball thrown downward?
A ski jumper starts from rest 50.0 m above the ground on a frictionless track and flies off the track at an angle of 45.0 above the horizontal and at a height of 10.0 m above the level ground. Neglect air resistance, (a) What is her speed when she leaves the track? (b) What is the maximum altitude she attains after leaving the track? (c) Where does she land relative to the end of the track?
Show that when A+B=C then A2+B2+2ABcos , where is the angle between vectors A and B .
Why is the following situation impossible? In a new casino, a supersized pinball machine is introduced. Casino advertising boasts that a professional basketball player can lie on top of the machine and his head and feet will not hang off the edge! The ball launcher in the machine sends metal balls up one side of the machine and then into play. The spring in the launcher (Fig. P6.60) has a force constant of 1.20 N/cm. The surface on which the ball moves is inclined = 10.0 with respect to the horizontal. The spring is initially compressed its maximum distance d = 5.00 cm. A ball of mass 100 g is projected into play by releasing the plunger. Casino visitors find the play of the giant machine quite exciting.
A Nordic jumper goes off a ski jump at an angle of 10.0 below the horizontal, traveling 108 m horizontally and 55.0 m vertically before landing. (a) Ignoring friction and aerodynamic effects. calculate the speed needed by the skier on leaving the ramp. (b) Olympic Nordic jumpers can make such jumps with a jump speed of 23.0 m/s, which is considerably less than the answer found in pan (a). Explain how that is possible
An 80.0-kg skydiver jumps out of a balloon at an altitude of 1.00 103 m and opens the parachute at an altitude of 200.0 m. (a) Assuming that the total retarding force on the diver is constant at 50.0 N with the parachute closed and constant at 3.60 103 N with the parachute open, what is the speed of the diver when he lands on the ground? (b) Do you think the skydiver will get hurt? Explain. (c) At what height should the parachute be opened so that the final speed of the skydiver when he hits the ground is 5.00 m/s? (d) How realistic is the assumption that the total retarding force is constant? Explain.
Review. A 3.00-kg block starts from rest at the top of a 30.0 incline and slides a distance of 2.00 m down the incline in 1.50 s. Find (a) the magnitude of the acceleration of the block, (b) the coefficient of kinetic friction between block and plane, (c) the friction force acting on the block, and (d) the speed of the block after it has slid 2.00 m.