Clearly state the formulae you’re using and what your letters/symbols mean. A child of mass 25 kg is sledding on the slope shown. At position \( A \), the sled is moving at 12 m/s. Find the speed of the sled at point \( B \) if the work done by friction has a magnitude of 80 J.### Diagram Explanation:- **Slope Diagram**: The diagram depicts a sledding path with two key points labeled \( A \) and \( B \).- **Point A**: - The sled is initially at position \( A \), with a velocity (\( v_A \)) of 12 m/s. - The height of point \( A \) from the ground is 20 m.- **Point B**: - The sled moves to position \( B \), which is at a lower height of 10 m from the ground.- **Motion Path**: The sled travels down a slope from \( A \) to \( B \).- **Friction Work**: The work done by friction as the sled moves between these points is given as 80 J. This scenario likely involves principles of energy conservation, such as kinetic and potential energy changes, taking into account the work done by friction.

SOlution: as given thatthe total enrgy at the point AEA = mgh+0.5mv2-WfWf - work done by frictionEA =25x9.81(20-10)+0.5x25x122-80EA =4175.5 Jnow the enrgy at the point B is given byEB = 0.5mv2since we heve already deducted the potential energy at B from point Aso, EA =EB4175.5 = 0.5mv24175.5 = 0.5x25xv2v = 18.27 m/sthe velocity at point B is 18.27 m/s