A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data. Isotope K-39 K-41 Relative abundance 93.12 % 6.88 % Their setup and calculation are. Mass (amu) 38.964 40.962 X Atomic Mass 38.964 amu 40.962 amu Relative Abundance (% divide by 100) 0.0688 What did the student do incorrectly? Use CER! 0.9312 = 2.681 = 38.144 40.823 amu The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table.
A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data. Isotope K-39 K-41 Relative abundance 93.12 % 6.88 % Their setup and calculation are. Mass (amu) 38.964 40.962 X Atomic Mass 38.964 amu 40.962 amu Relative Abundance (% divide by 100) 0.0688 What did the student do incorrectly? Use CER! 0.9312 = 2.681 = 38.144 40.823 amu The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Concept explainers
Atomic Structure
The basic structure of an atom is defined as the component-level of atomic structure of an atom. Precisely speaking an atom consists of three major subatomic particles which are protons, neutrons, and electrons. Many theories have been stated for explaining the structure of an atom.
Shape of the D Orbital
Shapes of orbitals are an approximate representation of boundaries in space for finding electrons occupied in that respective orbital. D orbitals are known to have a clover leaf shape or dumbbell inside where electrons can be found.
Question
100%
What did the student do incorrectly
Use CER!
Claim: (answer the question)
Evidence: (point readers to the part of the image that supports your claim)
Reasoning: (define and use the definition to support why you pointed to that part of the image.)
An example of a chemistry CER is the second image.
Transcribed Image Text:**CLAIM:** (Answer the question.)
The half-life is about 11 seconds.
---
**EVIDENCE:** (Point readers to the part of the image that supports your claim.)
We have to locate the amount of radioactive material (nuclei) and we need to find its quantity 50%. So, point y-axis at 50% and move your pointer towards time which is on the x-axis and note. Doing this I found that the half-life is 11 seconds.
---
**REASONING:** (Define half-life and use this definition to support why you pointed to a specific part of the image to make your claim.)
Half-life is the time it takes for half of the original amount of a radioactive sample to decay. On the y-axis, when undecayed nuclei is 50%, it means 50% of nuclei has reacted and it gives the half-life of an isotope.
Transcribed Image Text:**Title: Average Atomic Mass Calculation of Potassium**
A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data:
| Isotope | Relative Abundance | Atomic Mass (amu) |
|---------|---------------------|-------------------|
| K-39 | 93.12% | 38.964 |
| K-41 | 6.88% | 40.962 |
**Setup and Calculation:**
The student's setup involves multiplying the atomic mass of each isotope by its relative abundance (converted to a decimal), and then summing these values to find the average atomic mass.
| Mass (amu) | x Relative Abundance (% divided by 100) | Result |
|------------|----------------------------------------|------------|
| 38.964 | 0.0688 | = 2.681 |
| 40.962 | 0.9312 | = 38.144 |
| **Average Atomic Mass** | | **40.823 amu** |
**Discussion:**
The student calculated the average atomic mass to be 40.823 amu, but according to the periodic table, it is 39.098 amu.
**Question:**
What did the student do incorrectly? Use CER (Claim, Evidence, Reasoning) to explain the mistake.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY