A chemist titrates 90.0 mL of a 0.3491M aniline (C6H5NH₂) solution with 0.0636M HBr solution at 25 °C. Calculate the pH at equivalence. The p K₁ of aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = 0 X
A chemist titrates 90.0 mL of a 0.3491M aniline (C6H5NH₂) solution with 0.0636M HBr solution at 25 °C. Calculate the pH at equivalence. The p K₁ of aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = 0 X
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![A chemist titrates 90.0 mL of a 0.3491 M aniline \((C_6H_5NH_2)\) solution with 0.0636 M HBr solution at 25 °C. Calculate the pH at equivalence. The \(pK_b\) of aniline is 4.87.
Round your answer to 2 decimal places.
*Note for advanced students:* you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added.
\[ \text{pH} = \boxed{} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabd5e741-0235-409f-80de-883f5f0e5da7%2F85a8b27d-3412-4701-85a4-7c499f3e5d14%2F9hkw37_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A chemist titrates 90.0 mL of a 0.3491 M aniline \((C_6H_5NH_2)\) solution with 0.0636 M HBr solution at 25 °C. Calculate the pH at equivalence. The \(pK_b\) of aniline is 4.87.
Round your answer to 2 decimal places.
*Note for advanced students:* you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added.
\[ \text{pH} = \boxed{} \]
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