A cheese ripening room which, has a total surface area of A = 25.0m², has to ensure that the inside temperature does not exceed 11.0°C at all times. If the maximum outside temperature is 35.0°C and the cheese ripening room has an air conditioner which provides 125 kW of cooling, calculate the how thick the wooden walls would need to bein mm, in order to ensure the inside temperature does not go above 11.0°C. Assume that the thermal Assume that the entire cheese ripening room is made of wood (induding ceiling and floor) and ignore any losses through the door as it kA(Tingide -Toutside ) conductivity, k of wood is 0.0800 m.C remains closed most of the time and is well sealed. Given: P =:

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Chapter1: Units, Trigonometry. And Vectors
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A cheese ripening room which, has a total surface area of A = 25.0m2, has to ensure that
the inside temperature does not exceed 11.0°C at all times. If the maximum outside
temperature is 35.0°C and the cheese ripening room has an air conditioner which provides
125 kW of cooling, calculate the how thi ck the wooden walls would need to bein mm, in
order to ensure the inside temperature do es not go above 11.0°C. Assume that the thermal
W
conductivity, k of wood is 0.0800
Assume that the entire cheese ripening room is
m.C
made of wood (including ceiling and floor) and ignore any losses through the door as it
remains closed most of the time and is well sealed. Given: P = KA(Tinside –Toutside )
L
Transcribed Image Text:A cheese ripening room which, has a total surface area of A = 25.0m2, has to ensure that the inside temperature does not exceed 11.0°C at all times. If the maximum outside temperature is 35.0°C and the cheese ripening room has an air conditioner which provides 125 kW of cooling, calculate the how thi ck the wooden walls would need to bein mm, in order to ensure the inside temperature do es not go above 11.0°C. Assume that the thermal W conductivity, k of wood is 0.0800 Assume that the entire cheese ripening room is m.C made of wood (including ceiling and floor) and ignore any losses through the door as it remains closed most of the time and is well sealed. Given: P = KA(Tinside –Toutside ) L
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