A thin glaze is applied on the surface of a thick ceramic block by heating it above 650◦C, which allows it to flow over the surface. On cooling, the glaze becomes sufficiently stiff at 500◦C to act as a solid (Fig. 3). Calculate the stresses in the glaze layer by assuming it to be in a state of plane stress in the X1 − X2 plane when it has cooled to 20◦C. The thermal expansion coefficients of the glaze (g) and ceramic (c) are respectively, αg = 4.0 × 10−6/◦C and αc = 5.5×10−6/◦C. Take E = 300GPa and ν = 0.15 for the glaze and the block. Assume the stresses in the block to be negligible. A thin glaze is applied on the surface of a thick ceramic block by heating it above 650°C,which allows it to flow over the surface. On cooling, the glaze becomes sufficiently stiff at500°C to act as a solid (Fig. 3). Calculate the stresses in the glaze layer by assuming it tobe in a state of plane stress in the X1expansion coefficients of the glaze (g) and ceramic (c) are respectively, a, = 4.0 × 10–6/°Cand ac =X2 plane when it has cooled to 20°C. The thermal5.5 x 10-6/°C. Take Ethe stresses in the block to be negligible.= 300GPA and v = 0.15 for the glaze and the block. AssumeX3X2GlazeBlockFigure 3

Given that : FA = -E a dT / v , this is the formula to find the thermal expansion of the stress. dT…

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