A charged particle is fired into a cubical region of space where there is a uniform magnetic field. Outside this region, there is no magnetic field. Is it possible that the particle will remain inside the cubical region? Why or why not?

Q: An electron is accelerated from rest through a square parallel plate capacitor C1 with a charge…

A: We are given charge on capacitor. We find potential of capacitor. We then find field and hence force…

Q: An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of…

A: Given values: Magnetic field,B=3.50 mT Angular momentum, L=3.00×10-25 Js Mass of electron,…

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A: Given : V = 3 kV = 3000 V r = 15 cm = 0.15 m

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Q: A proton has a magnetic field due to its spin on its axis. The field is similar to that created by a…

A: The maximum torque on the proton is given by τ=NIAB sinθ

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Q: The ions entering the mass spectrometer have the same charges. After being accelerated through a…

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A: Current I=5 A Distance, d=0.4 cm = 0.004 m Charge, q=1 C Velocity, v=1.9 m/s

Q: An electron (charge −e) orbits with speed 2×10^6 [m/s] around a central proton (charge +e, along a…

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Q: A positive charge is moving in the direction shown in Figure Q24.18. The magnetic force on the…

A: To Find :  Direction of magnetic field when force on +ve charge particle is out of the page . Answer…

Q: 3) An electron is accelerated through a potential difference of 1 kV, then passes through a region…

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Q: proton moves at 4.0 x 10^6 m/s in a bubble chamber, perpendicular to a magnetic field. The radius of…

A: Speed, v = 4×106 m/sRadius, r = 6 cm = 0.06 mMass of proton, m = 1.67×10-27 kgCharge of proton, q =…

Q: After being accelerated to a speed of 1.89x105 m/s, the particle enters a uniform magnetic field of…

A: Given: Speed of particle = 1.89 ×105 m/s Magnetic field strength = 1.00 TRadius of circle = 34.0 cm…

Q: You observe an electron moving on your screen in a clockwise circle of radius 5.74 cm, at a constant…

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Q: A closed-current loop is commonly referred to as a magnetic dipole and the term IA (current * area…

A: Given data: Radius of current loop is, r=2.0 cm=0.02 m. Current through loop is, I=2.0 mA=2.0×10-3…

Q: An electron ( me = 9.11x10 31 kg q=1.6x1091 C) moves in a %3D circular path perpendicular to a…

A: The radius of the circular path can be obtained as r=mvqB

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Q: 1. Consider three particles moving in a magnetic field that is coming out of the page. (a) Are the…

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Q: A proton moving in a circular path perpendicular to a constant magnetic field takes 3.23 μs to…

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Q: An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 1.11…

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Q: A charged particle goes through half a circle in a uniform magnetic field B. If it spends 178 ns in…

A: Part (a): Charge enters from left to right and magnetic field direction is into the page. From…

Q: Q. 4: A proton moves through a uniform magnetic field given by B = (10 î- 20j +30k) mT. At a time…

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Q: An electron in the beam of a cathode-ray tube is accelerated by a potential difference of 2.00 kV.…

A: Where,Potential energy=Kinetic energythen, v=2eVmGiven e=1.6×10-19 CV=2.00×103 Vm=9.1×10-31 kg

Q: A proton has a magnetic field due to its spin on its axis. The field is similar to that created by a…

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Q: After being accelerated to a speed of 1.80×105 m/s, the particle enters a uniform magnetic field of…

A: The given data are: v=1.8×105 m/sB=0.8 Tr=30 cm=0.3 m Here, v, B,and r represent the speed, magnetic…

Q: You are observing an electron that is circling around in a magnetic field. You increase the magnetic…

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Q: An electron moves along the z-axis with vz=3.9×107m/svz=3.9×107m/s. As it passes the origin, what…

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Q: A Hydrogen atom can be thought of as a positive nucleus with a negatively charged electron, orbiting…

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Q: Show the magnetic dipole moment i using an explanation of physical and mathematical approaches. Show…

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Q: Same charged particles with masses of mi and m2 = 256-mı accelerated by the same potential…

A: LP

Q: A proton has a magnetic field due to its spin on its axis. The field is similar to that created by a…

A: The expression for torque will be

Q: In unit vector notation, find the magnetic force on the electron due to the current passing through…

A: Given, k= 8.987×109 Nm2/c2ε0=8.854×10-12 F/mμ0= 12.566×10-7 H/me=-1.6021×10-19 Cme= 9.1×10-31 kgR=…

Q: An electron in an old-fashioned TV camera tube is moving at 10.0 × 106 m/s in a magnetic field of…

A: Given: The magnitude of the electron's velocity: v = 10.0 x 106 m/s. The magnitude of the magnetic…

Q: ou observe an electron moving on your screen in a clockwise circle of radius 5.74 cm, at a constant…

A: Given data: An electron moving in uniform circular motion in presence of uniform magnetic field…

Q: A charged particle with charge 7.50x10^-19 moves at a constant speed and passes through a uniform…

A: Given:-          Charge of particle (q) = 7.5×10-19 C          Radius of circular path (r) = 1.4 cm…

Q: An unknown particle travelling with a velocity of 3.12 x 105 m/s enters a 54 mT magnetic field and…

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Q: After being accelerated to a speed of 1.92×105 m/s , the particle enters a uniform magnetic field of…

A: The given values are,

Q: . A charged particle moves in a horizontal plane with a speed of 8 70 106 . × m / s. When this…

A: We know that when a charge particle in uniform vertical field a perpendicular force act due to this…