A charged dust speck with mass, m = 4.1 g, loses 24 mJ of kinetic energy as it moves aross an electric potential, AV = -121 V. (a) How much work was done on the dust speck? Wnet = -24 mJ (b) What was the change in the dust speck's electric potential energy change, assuming that Wnet = WĘ? AU = |24 mJ (c) Find the charge on the dust speck. 24e-3 -121 Q = = -198.3 HC (d) What was the dust speck's final kinetic energy if it was initially moving at a speed of 4.19 m/s? Kf = (e) So, how fast was it after crossing the potential differene? Vf = m/s
A charged dust speck with mass, m = 4.1 g, loses 24 mJ of kinetic energy as it moves aross an electric potential, AV = -121 V. (a) How much work was done on the dust speck? Wnet = -24 mJ (b) What was the change in the dust speck's electric potential energy change, assuming that Wnet = WĘ? AU = |24 mJ (c) Find the charge on the dust speck. 24e-3 -121 Q = = -198.3 HC (d) What was the dust speck's final kinetic energy if it was initially moving at a speed of 4.19 m/s? Kf = (e) So, how fast was it after crossing the potential differene? Vf = m/s
Related questions
Question
100%
Transcribed Image Text:A charged dust speck with mass, m = 4.1 g, loses 24 mJ of kinetic energy as it moves aross an electric potential, AV = -121 V.
(a) How much work was done on the dust speck?
Wnet = -24
mJ
(b) What was the change in the dust speck's electric potential energy change, assuming that Wnet = WĘ?
AU = |24
mJ
(c) Find the charge on the dust speck.
24e-3
-121
Q =
= -198.3
HC
(d) What was the dust speck's final kinetic energy if it was initially moving at a speed of 4.19 m/s?
Kf =
(e) So, how fast was it after crossing the potential differene?
Vf =
m/s
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
