A charge Q is placed in the center of a shell of radius R. The electric flux through the shell surface is $0. If we now double the radius of the shell, what happens to the flux through its surface? It will increase by a factor of 4 It will increase by a factor of 2 It will decrease by a factor of 4 It will decrease by a factor of 2 It remains unchanged none of these

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A charge Q is placed in the center of a shell of radius R. The electric flux through the shell surface is
$0.
If we now double the radius of the shell, what happens to the flux through its surface?
It will increase by a factor of 4
It will increase by a factor of 2
It will decrease by a factor of 4
It will decrease by a factor of 2
It remains unchanged
none of these
Transcribed Image Text:A charge Q is placed in the center of a shell of radius R. The electric flux through the shell surface is $0. If we now double the radius of the shell, what happens to the flux through its surface? It will increase by a factor of 4 It will increase by a factor of 2 It will decrease by a factor of 4 It will decrease by a factor of 2 It remains unchanged none of these
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Given

Q charge is placed at the center of a shell and flux produced is Φo   .

If radius is doubled then what will happen to the flux.

 

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