A CG amplifier with: Im = 2 mA/V r, = 20 KN The input signal to this amplifier has a Norton equivalent circuit composed of a current signal isig and a source resistance Rig = 20 KN. The load of the amplifier is R, = 20 KN. The current through R, is i,. Find: Rin i,/isig
A CG amplifier with: Im = 2 mA/V r, = 20 KN The input signal to this amplifier has a Norton equivalent circuit composed of a current signal isig and a source resistance Rig = 20 KN. The load of the amplifier is R, = 20 KN. The current through R, is i,. Find: Rin i,/isig
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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
Transcribed Image Text:A CG amplifier with:
Im = 2 mA/V
r. = 20 KN
The input signal to this amplifier has a Norton equivalent circuit composed of a current signal
isig and a source resistance Rig = 20 Kn. The load of the amplifier is R, = 20 KN The current
through R, is i,.
Find:
Rin
• ilisig
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