A certain stretched string has a fundamental frequency for standing transverse waves of 440 Hz. The tension in the string is then increased by 21%. This tension increase changes the fundamental frequency to

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A certain stretched string has a fundamental frequency for standing transverse waves of 440 Hz.
The tension in the string is then increased by 21%. This tension increase changes the fundamental
frequency to
461 Hz
400 Hz
532 Hz
512 Hz
O 484 Hz
Transcribed Image Text:A certain stretched string has a fundamental frequency for standing transverse waves of 440 Hz. The tension in the string is then increased by 21%. This tension increase changes the fundamental frequency to 461 Hz 400 Hz 532 Hz 512 Hz O 484 Hz
Expert Solution
Given Data

Initial fundamental frequency = n = 440 Hz

Total tension after it increased by 21 % = T' = T + 0.21T = 1.21T

New fundamental frequency = n' =?

Here, we are using the same string, therefore the values of length (l), linear density (m) of the string are constant in both cases.

Solution

The fundamental frequency is

                                                n=12lTm                      . . . . . (i)

Where,

length of string = l

Tension in string = T

linear density of string  = m

The new fundamental frequency after increasing the tension is

                                              n'=12lT'm                      

Substituting T'= 1.21T

                                            n'=12l1.21Tm                      . . . . . (ii)

Divide equation (ii) by equation (i),

                                          n'n=1.21TT

Substituting the values,

                                          n'440=1.21

                                            n'=484 Hz

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