A certain shade of blue has a frequency of 7.08 x 10¹4 Hz. What is the energy of exactly one photon of this light? Planck's constant is h = 6.626 x 10-34 J-s. Attempt 1
A certain shade of blue has a frequency of 7.08 x 10¹4 Hz. What is the energy of exactly one photon of this light? Planck's constant is h = 6.626 x 10-34 J-s. Attempt 1
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Problem Description
A certain shade of blue has a frequency of \(7.08 \times 10^{14}\) Hz. What is the energy of exactly one photon of this light? Planck's constant is \(h = 6.626 \times 10^{-34}\) J·s.
### Given Formula
The energy of a photon can be calculated using the formula:
\[
E = h \cdot f
\]
where:
- \(E\) is the energy of the photon,
- \(h\) is Planck's constant \((6.626 \times 10^{-34} \text{ J·s})\),
- \(f\) is the frequency of the light.
### Calculation
1. Substitute the given frequency and Planck's constant into the formula:
\[
E = 6.626 \times 10^{-34} \, \text{J·s} \, \times \, 7.08 \times 10^{14} \, \text{Hz}
\]
### Incorrect Answer
The submitted answer was:
\[
E = 4.85 \times 10^{-19} \, \text{J}
\]
This answer was marked as incorrect.
### Discussion
Ensure that calculations are performed accurately, checking for possible decimal or calculation errors. The correct calculation according to the formula should be reviewed to determine the accurate energy value.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffdc195bb-9009-47db-866e-65b6514806e8%2F6a9144de-e8c5-4e53-8d06-bb588bf9e431%2Feid9yv7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Description
A certain shade of blue has a frequency of \(7.08 \times 10^{14}\) Hz. What is the energy of exactly one photon of this light? Planck's constant is \(h = 6.626 \times 10^{-34}\) J·s.
### Given Formula
The energy of a photon can be calculated using the formula:
\[
E = h \cdot f
\]
where:
- \(E\) is the energy of the photon,
- \(h\) is Planck's constant \((6.626 \times 10^{-34} \text{ J·s})\),
- \(f\) is the frequency of the light.
### Calculation
1. Substitute the given frequency and Planck's constant into the formula:
\[
E = 6.626 \times 10^{-34} \, \text{J·s} \, \times \, 7.08 \times 10^{14} \, \text{Hz}
\]
### Incorrect Answer
The submitted answer was:
\[
E = 4.85 \times 10^{-19} \, \text{J}
\]
This answer was marked as incorrect.
### Discussion
Ensure that calculations are performed accurately, checking for possible decimal or calculation errors. The correct calculation according to the formula should be reviewed to determine the accurate energy value.
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