A certain nonvolatile hydrocarbon that weighed 1.00 g was dissolved in 50.00 g of benzene. The resulting solution was boiled at 0.285 °C higher than the boiling point of pure benzene which boils at 80.1°C. Find the molar mass of the hydrocarbon. (Hint: See Table 1 for given constant.)
A certain nonvolatile hydrocarbon that weighed 1.00 g was dissolved in 50.00 g of benzene. The resulting solution was boiled at 0.285 °C higher than the boiling point of pure benzene which boils at 80.1°C. Find the molar mass of the hydrocarbon. (Hint: See Table 1 for given constant.)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Problem Solving:
1. A solution is made of 2.00 g of sucrose, C12H22011, in water, H20. The molar
mass (MM) of sucrose is 342 g/mol. Calculate the (a) boiling point and (h)
freezing point of the solution. (Hint: See Table 1 for given constants.)
2. A certain nonvolatile hydrocarbon that weighed 1.00 g was dissolved in
50.00 g of benzene. The resulting solution was boiled at 0.285 °C higher
than the boiling point of pure benzene which boils at 80.1°C. Find the molar
mass of the hydrocarbon. (Hint: See Table 1 for given constant.)
14

Transcribed Image Text:Table 1. Molal Freezing Point and Boiling Point Constants
Freezing Point
(C)
Solvent
Formula
Bolling Point
(*C)
(C/molal)
(c/molal)
Water
H20
0.0
1.86
100.0
0.51
Acetic acid CH:COOH 17.0
3.90
118.1
3.07
Benzene
5.5
4.90
80.2.
2.53
Chloroform CHC3
-63.5
4.68
61.2
3.63
Ethanol
C2H5OH
114.7
1.99
78.
78.4
1.22
7.40
181.0
3.56
Phenol
CeHsOH
43.0
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