A certain material has a yield stress limit in simple tension of 387 N/mm². The yield limit in compression can be taken to be equal to that in tension. The material is subjected to three stresses in mutually perpendicular directions, the stresses being in the ratio 3 : 2: –1.8. Determine the stresses that will cause failure according to the von Mises and Tresca theories of elastic failure. Ans. Tresca: 01= 241.8 N/mm², 01=161.2 N/mm², 0 =-145.1 N/mm². von Mises: o1= 264.0 N/mm², ơ1=176.0 N/mm², 0u=-158.4 N/mm².

Structural Analysis
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A certain material has a yield stress limit in simple tension of 387 N/mm². The yield limit in
compression can be taken to be equal to that in tension. The material is subjected to three
stresses in mutually perpendicular directions, the stresses being in the ratio 3 : 2: -1.8.
Determine the stresses that will cause failure according to the von Mises and Tresca theories of
elastic failure.
Ans. Tresca: o1 = 241.8 N/mm², ơ1=161.2 N/mm², o=-145.1 N/mm?.
von Mises: o1= 264.0 N/mm², ơn=176.0 N/mm², Om=-158.4 N/mm?.
Transcribed Image Text:A certain material has a yield stress limit in simple tension of 387 N/mm². The yield limit in compression can be taken to be equal to that in tension. The material is subjected to three stresses in mutually perpendicular directions, the stresses being in the ratio 3 : 2: -1.8. Determine the stresses that will cause failure according to the von Mises and Tresca theories of elastic failure. Ans. Tresca: o1 = 241.8 N/mm², ơ1=161.2 N/mm², o=-145.1 N/mm?. von Mises: o1= 264.0 N/mm², ơn=176.0 N/mm², Om=-158.4 N/mm?.
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