A certain material has a yield stress limit in simple tension of 387 N/mm². The yield limit in compression can be taken to be equal to that in tension. The material is subjected to three stresses in mutually perpendicular directions, the stresses being in the ratio 3 : 2: –1.8. Determine the stresses that will cause failure according to the von Mises and Tresca theories of elastic failure. Ans. Tresca: 01= 241.8 N/mm², 01=161.2 N/mm², 0 =-145.1 N/mm². von Mises: o1= 264.0 N/mm², ơ1=176.0 N/mm², 0u=-158.4 N/mm².

A certain material has a yield stress limit in simple tension of 387 N/mm². The yield limit in compression can be taken to be equal to that in tension. The material is subjected to three stresses in mutually perpendicular directions, the stresses being in the ratio 3 : 2: –1.8. Determine the stresses that will cause failure according to the von Mises and Tresca theories of elastic failure. Ans. Tresca: 01= 241.8 N/mm², 01=161.2 N/mm², 0 =-145.1 N/mm². von Mises: o1= 264.0 N/mm², ơ1=176.0 N/mm², 0u=-158.4 N/mm².

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A rigid block of mass M is supported by three symmetrically spaced rods as shown in figure. Each copper rod has an area of 900 mm^2; E = 120 GPa; and the allowable stress is 70 MPa. The steel rod has an area of 1200 mm^2; E = 200 GPa; and the allowable stress is 140 MPa. (a)Compute the stress of the copper rod. (b)Compute the stress of steel rod. (c)Compute the largest weight which can be supported.