A certain flight arrives on time 84 percent of the time. Suppose 155 flights are randomly selected. Use the normal approximation to the binomial to approximate the probability that:(a) exactly 125 flights are on time.\[ \text{P}(125) = \text{[ ] (Round to four decimal places as needed.)} \](b) at least 125 flights are on time.\[ \text{P}(X \geq 125) = \text{[ ] (Round to four decimal places as needed.)} \](c) fewer than 139 flights are on time.\[ \text{P}(X < 139) = \text{[ ] (Round to four decimal places as needed.)} \](d) between 139 and 143, inclusive, are on time.\[ \text{P}(139 \leq X \leq 143) = \text{[ ] (Round to four decimal places as needed.)} \]Enter your answer in each of the answer boxes.

Given, n=155 p=0.84 Now, np=155×0.84=130.2≥10np1-p=155×0.84×1-0.84=20.832≥10 Let X be the random…

A certain flight arrives on time 84 percent of the time. Suppose 155 flights are randomly selected. Use the normal approximation to the binomial to approximate the probability that (a) exactly 125 flights are on time. (b) at least 125 flights are on time. (c) fewer than 139 flights are on time. (d) between 139 and 143, inclusive are on time. (a) P(125) = (Round to four decimal places as needed.) (b) P(X2 125) = (Round to four decimal places as needed.) (c) P(X < 139) = (Round to four decimal places as needed.) (d) P(139

A certain flight arrives on time 84 percent of the time. Suppose 155 flights are randomly selected. Use the normal approximation to the binomial to approximate the probability that (a) exactly 125 flights are on time. (b) at least 125 flights are on time. (c) fewer than 139 flights are on time. (d) between 139 and 143, inclusive are on time. (a) P(125) = (Round to four decimal places as needed.) (b) P(X2 125) = (Round to four decimal places as needed.) (c) P(X < 139) = (Round to four decimal places as needed.) (d) P(139

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

In a large population, 67 % of the people have been vaccinated. If 4 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?Give your answer as a decimal to at 4 places
Assume that when adults with smartphones are randomly selected, 45% use them in meetings or classes. If 9 adult smartphone users are randomly selected, find the probability that at least 2 of them use their smartphones in meetings or classes. The probability is. (Round to four decimal places as needed.)
If a number is randomly chosen from the interval (-3,3). What is the probability that the number is less than −8/3? Suppose that a number is randomly chosen from the interval (-6,2). What is the probability that the number chosen within 2 units away from 1? NOTE: ROUND OFF your answer to FOUR DECIMAL places.
express the event "taking atleast 16 credits" in terms of X and find its probability
Assume that when adults with smartphones are randomly selected, 45% use them in meetings or classes. If 9 adult smartphone users are randomly selected, find the probability that at least 6 of them use their smartphones in meetings or classes. The probability is 0.9502. (Round to four decimal places as needed.) CHE
The probability is 0.0770 that the 6th applicant for a factory job will be hired on the 13th interview. What is the probability that 6 applicants will be hired from 13 applicants who have been interviewed? Your answer should be to 4 decimal places.
Ezra buys a bag of cookies that contains 9 chocolate chip cookies, 7 peanut butter cookies, 4 sugar cookies and 4 oatmeal cookies.What is the probability that Ezra reaches in the bag and randomly selects a peanut butter cookie from the bag, eats it, then reaches back in the bag and randomly selects a chocolate chip cookie? Give your answer as a fraction, or accurate to at least 4 decimal places.
The table summarizes results from 980 pedestrian deaths that were caused by automobile accidents. Driver Intoxicated? Pedestrian Intoxicated? Yes No Yes 60 69 No 238 613 If one of the pedestrian deaths is randomly selected, find the probability that both the pedestrian and the driver were intoxicated. Please enter a decimal to 4 places.
The table summarizes results from 988 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Intoxicated? Yes No Pedestrian Intoxicated? Yes No 42 85 250 611 If one of the pedestrian deaths is randomly selected, find the probability that neither the pedestrian nor the driver was intoxicated. Please enter a decimal to 4 places.
Assume that when adults with smartphones are randomly selected, 53% use them in meetings or classes. If 10 adult smartphone users are randomly selected, find the probability that at least 3 of them use their smartphones in meetings or classes. The probability is 0.0905 (Round to four decimal places as needed.)
Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes. If 10 adult smartphone users are randomly selected, find the probability that at least 8 of them use their smartphones in meetings or classes. The probability is. (Round to four decimal places as needed.)