A certain decomposition reaction is first order with a rate constant of 6.85*10-4 s-1 at 25 degrees Celsius. If the original concentration of reactant A is 0.365 M how long (in seconds) will it take for 1/3 of reactant A to have reacted?
A certain decomposition reaction is first order with a rate constant of 6.85*10-4 s-1 at 25 degrees Celsius. If the original concentration of reactant A is 0.365 M how long (in seconds) will it take for 1/3 of reactant A to have reacted?
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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A certain decomposition reaction is first order with a rate constant of 6.85*10-4 s-1 at 25 degrees Celsius.
If the original concentration of reactant A is 0.365 M how long (in seconds) will it take for 1/3 of reactant A to have reacted?
Expert Solution
Step 1) first order reaction
* First order reaction =>
Rate = [A]¹
OR
Kt = ln {A0/A}
Where,
K = rate constant
{ A0 } is intial concentration
{ A } is final concentration
t is take by reaction
* intial concentration {A0} = 0.365 M
And only 1/3 of reactant is reacted
So, final concentration of reactant = A0 - A0/3
final concentration = (3A0 - A0 ) / 3
final concentration = 2A0/3
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