The image contains a scenario involving a catalyzed reaction with an activation energy $ E_a = 8.0 \, \text{kJ/mol} $. The rate of this reaction is measured at $ 352. \, \text{K} $ and found to be $ 6.5 \times 10^6 \, \text{M/s} $.Students are asked to use this information to answer two questions presented in a table:1. **Temperature Increase Scenario:** - The concentrations of all reactants are kept the same, but the temperature is raised by 5% from $ 352. \, \text{K} $ to $ 370. \, \text{K} $. - Question: How will the rate of the reaction change? - Answer Option: A dropdown menu to choose whether the rate will increase, decrease, or stay the same.2. **Catalyst Removal Scenario:** - The concentrations of all reactants are kept the same, but the catalyst is removed, raising the activation energy by 10%, from $ 8.0 \, \text{kJ/mol} $ to $ 8.80 \, \text{kJ/mol} $. - Question: How will the rate of the reaction change? - Answer Option: A dropdown menu to choose whether the rate will increase, decrease, or stay the same.

Answered: A certain catalyzed reaction is known…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The image contains a scenario involving a catalyzed reaction with an activation energy $ E_a = 8.0 \, \text{kJ/mol} $. The rate of this reaction is measured at $ 352. \, \text{K} $ and found to be $ 6.5 \times 10^6 \, \text{M/s} $.

Students are asked to use this information to answer two questions presented in a table:

1. **Temperature Increase Scenario:**
- The concentrations of all reactants are kept the same, but the temperature is raised by 5% from $ 352. \, \text{K} $ to $ 370. \, \text{K} $.
- Question: How will the rate of the reaction change?
- Answer Option: A dropdown menu to choose whether the rate will increase, decrease, or stay the same.

2. **Catalyst Removal Scenario:**
- The concentrations of all reactants are kept the same, but the catalyst is removed, raising the activation energy by 10%, from $ 8.0 \, \text{kJ/mol} $ to $ 8.80 \, \text{kJ/mol} $.
- Question: How will the rate of the reaction change?
- Answer Option: A dropdown menu to choose whether the rate will increase, decrease, or stay the same.

Expert Solution

Step 1: Arrhenius equation

Answer:

These problems will be solved by using below shown forms of Arrhenius equation.

When activation energy remains the same but temperature changes then:

$ln straight k subscript 2 over straight k subscript 1 equals straight E subscript straight a over straight R open parentheses 1 over straight T subscript 1 minus 1 over straight T subscript 2 close parentheses space space space space space..... equation left parenthesis 1 right parenthesis$

When temperature remains the same but activation energy changes then:

$ln straight k subscript 2 over straight k subscript 1 equals 1 over RT left parenthesis straight E subscript straight a subscript 1 end subscript minus straight E subscript straight a subscript 2 end subscript right parenthesis space space space.... equation left parenthesis 2 right parenthesis$

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