A certain catalyzed reaction is known to have an activation energy E-70.0 kJ/mol. Furthermore, the rate of this reaction is measured at 372. K and found to be 1.5 x 10 M/s. Use this information to answer the questions in the table below. Suppose the concentrations of all reactants is kept the same, but the temperature is raised by 5% from 372. K to 391. K How will the rate of the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is removed, which has the effect of raising the activation energy by 10%, from 70.0 kJ/mol to 77.0 kJ/mol. How will the rate of the reaction change? The rate will The rate will choose one choose one

A certain catalyzed reaction is known to have an activation energy E-70.0 kJ/mol. Furthermore, the rate of this reaction is measured at 372. K and found to be 1.5 x 10 M/s. Use this information to answer the questions in the table below. Suppose the concentrations of all reactants is kept the same, but the temperature is raised by 5% from 372. K to 391. K How will the rate of the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is removed, which has the effect of raising the activation energy by 10%, from 70.0 kJ/mol to 77.0 kJ/mol. How will the rate of the reaction change? The rate will The rate will choose one choose one

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The rate of a certain reaction is given by the following rate law: rate =k[N,]H, ° Use this information to answer the questions below. olo What is the reaction order in N,? x10 Ar What is the reaction order in H,? What is overall reaction order? At a certain concentration of N, and H2, the initial rate of reaction is 0.090 M / s. What would the initial rate of the reaction be if the concentration of N, were doubled? Round M S your answer to 2 significant digits. The rate of the reaction is measured to be 95.0 M / s when [N2] = 0.99 M and [H2] = 1.1 M. Calculate the value of the -2 -1 k = •S rate constant. Round your answer to 2 significant digits.
13. The production of nitric oxide is governed by the following reaction: 4NH3(g) +502(g) → 4NO(g) + 6H2O(g). produced? If the rate at which NO is produced is 6.35 x 10-2 mol/ L*s, at what rate is H₂O a. 8.29 x 10-3 mol/L✶ s b. 9.53 x 10-2 mol/L*s c. 6.35 x 10-2 mol/L*s d. 7.94 x 10-2 mol/L*s 14. Sulfur trioxide production follows the reaction: 2 SO2(g) + O2(g) → 2 SO3(g) consumed? If the rate at which SO3 is produced is 4.28 x 10 mol L-'s-', at what rate is O2 a. 4.28 × 10-4 mol L-'s-1 b. 1.08 x 10-3 mol L-'s-1 c. 1.07 × 10-4 mol L-'s-1 d. 2.14 x 104 mol L-'s-1 15. Consider the following reaction: 2A+B→ C. A kinetics study on this reaction yielded the following data: [A] mol/L [B] mol/L Rate=mol/L/s 0.0450 0.0250 5.03 x 10-3 0.0450 0.0500 2.01 x 10-2 0.0900 0.0250 5.03 x 10-3 What is the order of the reaction with respect to ([A], [B])? a. 1, 2 b. 2, 1 c. 2, 0 d. 0, 2
The rate constant k for a certain reaction is measured at two different temperatures: temperature k 381.0 °C 5.1 x 10⁹ 321.0 °C 2.6 × 10⁹ Assuming the rate constant obeys the Arrhenius equation, calculate the activation energy E for this reaction. a Round your answer to 2 significant digits. kJ U E = a mol Ś ? 0 x10 X
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A certain catalyzed reaction is known to have an activation energy E= 11.0 kJ/mol. Furthermore, the rate of this reaction is measured at 296. K and found to be 1.1 × 10 M/s. Use this information to answer the questions in the table below. Suppose the concentrations of all reactants is kept the same, but the temperature is raised by 10% from 296. K to 326. K. How will the rate of the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is removed, which has the effect of raising the activation energy by 5%, from 11.0 kJ/mol to 11.6 kJ/mol. How will the rate of the reaction change? The rate will The rate will choose one choose one choose one stay the same rise about 5% rise more than 5% rise less than 5% fall about 5% fall more than 5% fall less than 5% V
The rate constant k for a certain reaction is measured at two different temperatures: temperature k 59.0 °C 6.5 x 101 14 163.0 °C |4.2 × 10 Assuming the rate constant obeys the Arrhenius equation, calculate the activation energy E, for this reaction. a Round your answer to 2 significant digits. kJ E x10 mol
The answer is C, please show steps, thanks.
A certain catalyzed reaction is Known to have an activation energy Ea=29.0 kJ/mol. Furthermore, the rate of this reaction is measured at 331 K and found to be 2.7× 10* M/s. Use this information to answer the questions in the table below. Suppose the concentrations of all reactants is kept the same, but the temperature is raised by 10% from 331 K to 364 K. How will the rate or the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is removed which has the eftect of raising the activation energy by 10%, from 29.0 kJ/mol to 31.9 kJ mol How will the rate or the reaction change?
9.
Consider a reaction A → B with activation energy 50.7 kJ/mol. At 19.5 °C, the rate constant, k, for this reaction is 0.095 s−1. Calculate the temperature, T (in °C), at which k = 0.329 s−1. Assume the pre-exponential factor (A) is constant with temperature. �=0.08206 L⋅atmmol⋅K=8.314 Jmol⋅K �K=�∘C+273.15 1 kJ = 1000 J Report your answer to three significant figures without the unit. Example: 20.0. Be sure that your answer is in °C and not Kelvin!
Deducing a rate law from initial reaction rate data Some measurements of the initial rate of a certain reaction are given in the table below. N2 Hinitial rate of reaction 2.21 M 2.33 M 35.0 M/s 2.21 M 4.98 M 160. M/s 7.27 M 2.33 M 379. M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbol. rate = k M k = Explanation Check 2021 McGraw Hill Educabon. All R P Type here to search 近