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A certain cable, 504.76 ft long is suspended between two supports at the same elevation and 500 ft apart, the load is 500 lbs per horizontal foot including the weight of the cable. Calculate the sag of this cable using Newton-Raphson method up to 5 iterations with initial guess of d (sag) 10 ft. Use parabolic equation. Parabolic Equation: 8d? s = L+ 3L 32d4 5L3 Where: S length of the cable distance between two supports

A certain cable, 504.76 ft long is suspended between two supports at the same elevation and 500 ft apart, the load is 500 lbs per horizontal foot including the weight of the cable. Calculate the sag of this cable using Newton-Raphson method up to 5 iterations with initial guess of d (sag) 10 ft. Use parabolic equation. Parabolic Equation: 8d? s = L+ 3L 32d4 5L3 Where: S length of the cable distance between two supports

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A certain cable, 504.76 ft long is suspended between two supports at the same elevation and 500 ft apart, the load is 500 lbs per horizontal foot including the weight of the cable. Calculate the sag of this cable iterations with initial guess of d using Newton-Raphson method up to 5 10 ft. Use parabolic equation. (sag) Parabolic Equation: 8d? 32d* s = L+ 3L 5L3 Where: length of the cable S L distance between two supports
Transcribed Image Text:A certain cable, 504.76 ft long is suspended between two supports at the same elevation and 500 ft apart, the load is 500 lbs per horizontal foot including the weight of the cable. Calculate the sag of this cable iterations with initial guess of d using Newton-Raphson method up to 5 10 ft. Use parabolic equation. (sag) Parabolic Equation: 8d? 32d* s = L+ 3L 5L3 Where: length of the cable S L distance between two supports
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