A certain alkyl halide, R-X, undergoes an elimination reaction. The observed rate law for this reaction is: Rate = k(R-X). What is the mechanism for this reaction? Select one: O A. E2 O B. E1 O C. O D. SN2 SN1
A certain alkyl halide, R-X, undergoes an elimination reaction. The observed rate law for this reaction is: Rate = k(R-X). What is the mechanism for this reaction? Select one: O A. E2 O B. E1 O C. O D. SN2 SN1
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Transcription for Educational Website**
A certain alkyl halide, R-X, undergoes an elimination reaction. The observed rate law for this reaction is:
\[ \text{Rate} = k(\text{R-X}) \]
What is the mechanism for this reaction?
**Select one:**
- ○ A. E2
- ○ B. E1
- ○ C. S<sub>N</sub>2
- ○ D. S<sub>N</sub>1
**Explanation:**
This question addresses the mechanism by which an alkyl halide undergoes an elimination reaction. The rate law provided is first-order, dependent solely on the concentration of the alkyl halide (R-X). This information suggests that the reaction mechanism is likely a unimolecular process.
**Key Considerations:**
- **E2 Mechanism:** Bimolecular elimination, where the rate depends on both the alkyl halide and the base. This does not fit the given first-order rate law.
- **E1 Mechanism:** Unimolecular elimination, which fits the first-order rate law and involves the formation of a carbocation intermediate.
- **S<sub>N</sub>2 Mechanism:** Bimolecular nucleophilic substitution, dependent on both the nucleophile and the substrate, typically resulting in a second-order rate law.
- **S<sub>N</sub>1 Mechanism:** Unimolecular nucleophilic substitution, which also demonstrates a first-order dependence on the substrate, similar to E1, but leads to substitution rather than elimination.
Given the context, the E1 mechanism is the most appropriate choice for the elimination reaction described by the rate law.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc14b7619-7f42-456d-bd15-e2d5f2d4f203%2F6b18ca51-39e0-4d7d-82ba-445a563d2be5%2Fnz9im6p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website**
A certain alkyl halide, R-X, undergoes an elimination reaction. The observed rate law for this reaction is:
\[ \text{Rate} = k(\text{R-X}) \]
What is the mechanism for this reaction?
**Select one:**
- ○ A. E2
- ○ B. E1
- ○ C. S<sub>N</sub>2
- ○ D. S<sub>N</sub>1
**Explanation:**
This question addresses the mechanism by which an alkyl halide undergoes an elimination reaction. The rate law provided is first-order, dependent solely on the concentration of the alkyl halide (R-X). This information suggests that the reaction mechanism is likely a unimolecular process.
**Key Considerations:**
- **E2 Mechanism:** Bimolecular elimination, where the rate depends on both the alkyl halide and the base. This does not fit the given first-order rate law.
- **E1 Mechanism:** Unimolecular elimination, which fits the first-order rate law and involves the formation of a carbocation intermediate.
- **S<sub>N</sub>2 Mechanism:** Bimolecular nucleophilic substitution, dependent on both the nucleophile and the substrate, typically resulting in a second-order rate law.
- **S<sub>N</sub>1 Mechanism:** Unimolecular nucleophilic substitution, which also demonstrates a first-order dependence on the substrate, similar to E1, but leads to substitution rather than elimination.
Given the context, the E1 mechanism is the most appropriate choice for the elimination reaction described by the rate law.
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