= A CE amplifier is made using a PNP transistor. Instead of a resistor, the load is an NPN transistor. Both transistors have Is = 5451 aA, while VA,n 78 V and VA,p = 234 V. The NPN is biased with 0.53 V such that the large signal swing of the output is maximized. VIN- 1.8 V VBIAS Q2 2. Compute for the value of Ic. 0100 μA 03.9 μA O100 NA 03.9 nA 3. What is the value of R₂? Use ß = 45. O300 ΚΩ 0100 GO 060 MQ O∞ VOUT PNP-based CE with NPN-based Active Load

= A CE amplifier is made using a PNP transistor. Instead of a resistor, the load is an NPN transistor. Both transistors have Is = 5451 aA, while VA,n 78 V and VA,p = 234 V. The NPN is biased with 0.53 V such that the large signal swing of the output is maximized. VIN- 1.8 V VBIAS Q2 2. Compute for the value of Ic. 0100 μA 03.9 μA O100 NA 03.9 nA 3. What is the value of R₂? Use ß = 45. O300 ΚΩ 0100 GO 060 MQ O∞ VOUT PNP-based CE with NPN-based Active Load

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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