A “cause” occurs at point 1 (x1, t1) and its “effect” occurs at point 2 (x2, t2). Use the Lorentz transformation to find t′2 − t′1, and showthat t′2 − t′1 > 0; that is, O′ can never see the “effect” coming before its “cause.
A “cause” occurs at point 1 (x1, t1) and its “effect” occurs at point 2 (x2, t2). Use the Lorentz transformation to find t′2 − t′1, and showthat t′2 − t′1 > 0; that is, O′ can never see the “effect” coming before its “cause.
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Question
A “cause” occurs at point 1 (x1, t1) and its “effect” occurs
at point 2 (x2, t2). Use the Lorentz transformation to
find t′2 − t′1, and showthat t′2 − t′1 > 0; that is, O′ can never
see the “effect” coming before its “cause.”
Expert Solution
Step 1
Given that,
A “cause” occurs at point 1 (x1, t1) and its “effect” occurs at point 2 (x2, t2).
We need to show that:
t′2 − t′1 > 0 by using Lorentz transformation; that is, O′ can never see the “effect” coming before its “cause.”
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