A cast iron cylinder has outside and inside diameter 200mm and 125mm respectively. If the ultimate strength of cast iron is 150MPa calculate according to each of the following theories of failure the internal pressure that will cause fracture.(a) Maximum principal stress theory. (b) Maximum principal strain theory. (c) Maximum strain energy theory. Assume no longitudinal stress in the cylinder. Which of the results obtained you consider should be applied to this case. Take:µ = 0.25, σU = 150MPa. Ans: (a) 65.73MPa. (b) 59.24MPa, (c) 55.33MPa.
A cast iron cylinder has outside and inside diameter 200mm and 125mm respectively. If the ultimate strength of cast iron is 150MPa calculate according to each of the following theories of failure the internal pressure that will cause fracture.(a) Maximum principal stress theory. (b) Maximum principal strain theory. (c) Maximum strain energy theory. Assume no longitudinal stress in the cylinder. Which of the results obtained you consider should be applied to this case. Take:µ = 0.25, σU = 150MPa. Ans: (a) 65.73MPa. (b) 59.24MPa, (c) 55.33MPa.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A cast iron cylinder has outside and inside diameter 200mm and 125mm
respectively. If the ultimate strength of cast iron is 150MPa calculate according to each of the following theories of failure the internal pressure that will cause fracture.(a) Maximum principal stress theory. (b) Maximum principal strain theory. (c) Maximum strain energy theory. Assume no longitudinal stress in the cylinder. Which of the results obtained you consider should be applied to this case. Take:µ = 0.25, σU = 150MPa.
Ans: (a) 65.73MPa. (b) 59.24MPa, (c) 55.33MPa.
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