**Scenario: Distributing Change Using Python**A cashier distributes change using the maximum number of five-dollar bills, followed by one-dollar bills. Write a single statement that assigns `num_ones` with the number of distributed one-dollar bills given `amount_to_change`. Hint: Use `%`.**Sample Output with Input: 19**```Change for $193 five dollar bill(s) and 4 one dollar bill(s)```**Python Code Explanation:**```python1 amount_to_change = int(input()) # Takes user input for the amount to change2 num_fives = amount_to_change // 5 # Calculates the maximum number of five-dollar bills3 num_ones = amount_to_change % 5 # Calculates the remaining one-dollar bills45 print('Change for $', amount_to_change) # Prints the total amount to change6 print(num_fives, 'five dollar bill(s) and', # Prints breakdown of five and one-dollar bills7 num_ones, 'one dollar bill(s)')```- **Line 1:** Prompts the user to enter the amount for which change is required and converts it to an integer.- **Line 2:** Uses integer division to calculate the maximum number of five-dollar bills.- **Line 3:** Uses the modulus operator to calculate the remaining amount, which will be the number of one-dollar bills.- **Line 5 & 6:** Prints out the total change, and the number of five and one-dollar bills needed.This program efficiently determines how to dispense a given amount using the fewest number of bills, prioritizing larger denominations.

There were a couple of bugs in the code provided in the question. These bugs have been fixed, and…

Answered: A cashier distributes change using the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write a statement to add the key Tesla with value USA to car_makers. Modify the car maker of Fiat to Italy. Sample output for the given program:
Using the celsius_to_kelvin function as a guide, create a new function, change the name to kelvin_to_celsius, and modify the function accordingly.Sample output with input: 283.1510.0 C is 283.15 K 283.15 K is 10.0 C def celsius_to_kelvin(value_celsius): value_kelvin = 0.0 value_kelvin = value_celsius + 273.15 return value_kelvin INSERT CODE value_c = 10.0print(value_c, 'C is', celsius_to_kelvin(value_c), 'K') value_k = float(input())print(value_k, 'K is', kelvin_to_celsius(value_k), 'C')
Write an expression that continues to bid until the user enters 'n'.Sample output with inputs: 'y' 'y' 'n'I'll bid $7! Continue bidding? I'll bid $15! Continue bidding? I'll bid $23! Continue bidding? import randomrandom.seed(5) keep_bidding = '-'next_bid = 0 while ''' Your solution goes here ''':next_bid = next_bid + random.randint(1, 10)print('I\'ll bid ${}!'.format(next_bid))print('Continue bidding?', end=' ')keep_bidding = input()
Create a program that will accept a number that will be the basis of the number of times a user can input different numeric values. The user will then input numbers based on the initial input. Identify the sum/total of all numbers but segregating the total for ODD and EVEN. Display the sum of both ODD and EVEN. Sample output: Please enter the count of input: 5 Please input No.1: 3 Please input No.2: 2 Please input No.3: 10 Please input No.4: 7 Please input No.5: 1 The total no of ODD is 3 and the sum is 11. The total no of EVEN is 2 and the sum 12. Using Matlab. Thanks!
Use cin to read integer leftoverValue from input. Then, read the remaining integers from input until 99 is read. For each remaining integer read before 99, if the integer is positive, output the positive integer followed by a newline and subtract the positive integer from leftoverValue. Ex: If the input is: 57 -25 24 20 99 then the output is: 24 20 The total after subtracting all positive values is 13 Note: leftoverValue may go negative. 1 #include 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13} int inputData; int leftoverValue; *Your code goes here */ cout << "The total after subtracting all positive values is " << leftoverValue << endl; return 0;

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