A Cascade refrigeration system using flash tank and intercooler is operating an evaporator with a capacity of 6 tons at a temperature of -30°C. The flash tank and intercooler is operated at 0.40 MPa. If the condensing temperature is 50°C, determine the COP and the refrigerating efficiency of the system. Draw the schematic diagram of the system and assume ideal conditions.Using R-32 p-h chart 10020200300400500R-3260070080020.(difluoromethane)10Reference state:h = 200.0 kJ/kg, s= 1.00 kJ/(kg K)for saturated liquid at 0°C8700600 -500-400300= 200 kg/m3615010.481008060506024404030302010.810200.6151-100.4100.88.0.-200.66.00.2T=-30°C0.4Il 4 4.0-403.00.10.20.08-502.00.061.5-600.10.041.00.080.800.06-700.600.020.040.40-803.200.300.010.023.300.20100200300Properties computed with: NIST REFPROP4005006000.01800version 7.0ENTHALPY, kJ/kg700Based on formulation of Tillner-Roth and Yokozeki (1997)PRESSURE, MPa-80 1300-701250:09-0.40* 0.5040--30Saturated Liquid--1150--0.70-200.1-100.8011000.90도0.2.10,1050-1000:1.100.31.201.30x30.41.400061.50#0.500-0.60.7- 2.10...0.82.20-2.300.9- 2.402.50Saturated Vapor2.60-202.8060-0608120= 3.10 kJ/(kg-140T= 180°C0072.

Given: Refrigeration capacity→RC=6 ton=6×3.5=21 KW According to the given condition TS diagram of…

Answered: A Cascade refrigeration system using…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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A Cascade refrigeration system using flash tank and intercooler is operating an evaporator with a capacity of 6 tons at a temperature of -30°C. The flash tank and intercooler is operated at 0.40 MPa. If the condensing temperature is 50°C, determine the COP and the refrigerating efficiency of the system. Draw the schematic diagram of the system and assume ideal conditions.

Using R-32 p-h chart

100
20
200
300
400
500
R-32
600
700
800
20.
(difluoromethane)
10
Reference state:
h = 200.0 kJ/kg, s= 1.00 kJ/(kg K)
for saturated liquid at 0°C
8
700
600 -
500-
400
300
= 200 kg/m3
6
150
10.
4
8
100
80
60
50
60
2
4
40
40
30
30
20
1
0.8
10
20
0.6
15
1
-10
0.4
10
0.8
8.0.
-20
0.6
6.0
0.2
T=-30°C
0.4
Il 4 4.0
-40
3.0
0.1
0.2
0.08
-50
2.0
0.06
1.5
-60
0.1
0.04
1.0
0.08
0.80
0.06
-70
0.60
0.02
0.04
0.40
-80
3.20
0.30
0.01
0.02
3.30
0.20
100
200
300
Properties computed with: NIST REFPROP
400
500
600
0.01
800
version 7.0
ENTHALPY, kJ/kg
700
Based on formulation of Tillner-Roth and Yokozeki (1997)
PRESSURE, MPa
-80 1300
-70
1250:
09-
0.40
* 0.50
40-
-30
Saturated Liquid
--1150-
-0.70
-20
0.1
-10
0.80
1100
0.90
도0.2.
10,
1050-
1000:
1.10
0.3
1.20
1.30
x30.4
1.40
006
1.50
#0.5
00-
0.6
0.7
- 2.10
...
0.8
2.20
-2.30
0.9
- 2.40
2.50
Saturated Vapor
2.60
-20
2.80
60-
06
08
120
= 3.10 kJ/(kg-
140
T= 180°C
007
2.

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