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A Carnot engine whose sink is at 300 K has an efficiency of 40%. By how much should the temperature of source be increased so as to increase its efficiency by 50% of original efficiency?

A Carnot engine whose sink is at 300 K has an efficiency of 40%. By how much should the temperature of source be increased so as to increase its efficiency by 50% of original efficiency?

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A Carnot engine whose sink is at 300 K has an efficiency of 40%. By how much should the temperature of source be increased so as to increase its efficiency by 50% of original efficiency?
Transcribed Image Text:A Carnot engine whose sink is at 300 K has an efficiency of 40%. By how much should the temperature of source be increased so as to increase its efficiency by 50% of original efficiency?
Expert Solution
Step 1

As given in the question,

Temperature of sink = TL = 300 K

Initial efficiency of Carnot engine = η1 = 40 % = 0.4

New efficiency of Carnot engine = η2 = Original efficiency + 50 % of original efficiency = 0.4 + (50% of 0.4) = 0.6

 

Let us take,

Initial temperature of source = TH1

New temperature of source = TH2

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