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A car of mass 1600 kg starts from rest on a level road and reaches a speed of 80 km/h in 33 s. a) What is the kinetic energy of the car at the end of 33 s? b) What is the average net power developed by the car during the 33 s interval? c) What is the instantaneous power at the end of the 33 s interval assuming that the acceleration was constant?

A car of mass 1600 kg starts from rest on a level road and reaches a speed of 80 km/h in 33 s. a) What is the kinetic energy of the car at the end of 33 s? b) What is the average net power developed by the car during the 33 s interval? c) What is the instantaneous power at the end of the 33 s interval assuming that the acceleration was constant?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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段階的に解決し、 人工知能を使用せず、 優れた仕事を行います ご支援ありがとうございました SOLVE STEP BY STEP IN DIGITAL FORMAT DON'T USE AI | DON'T USE AI | DON'T USE AI | DON'T USE AI | A car of mass 1600 kg starts from rest on a level road and reaches a speed of 80 km/h in 33 s. a) What is the kinetic energy of the car at the end of 33 s? b) What is the average net power developed by the car during the 33 s interval? c) What is the instantaneous power at the end of the 33 s interval assuming that the acceleration was constant?
Transcribed Image Text:段階的に解決し、 人工知能を使用せず、 優れた仕事を行います ご支援ありがとうございました SOLVE STEP BY STEP IN DIGITAL FORMAT DON'T USE AI | DON'T USE AI | DON'T USE AI | DON'T USE AI | A car of mass 1600 kg starts from rest on a level road and reaches a speed of 80 km/h in 33 s. a) What is the kinetic energy of the car at the end of 33 s? b) What is the average net power developed by the car during the 33 s interval? c) What is the instantaneous power at the end of the 33 s interval assuming that the acceleration was constant?
Expert Solution
Step 1: Given data

Mass of the automobile m equals 1600 k g

Final speed v subscript f equals 80 fraction numerator k m over denominator h end fraction equals 22.22 m over s

Time for the motion t subscript f equals 33 s

a)

The kinetic K of an object with the mass m and the speed vf is

K equals 1 half m v subscript f squared K equals 1 half cross times 1600 cross times 22.22 squared K equals 3.9 cross times 10 to the power of 5 J

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