If the roller coaster car at the top of the 95.0 m drop hill has a speed of 2.25 m/s, (a) what willbe its speed at the bottom of the hill if we assume that net work done by non-conservativeforces is zero? (b) Given that the actual speed of the roller coaster car at the bottom of thedrop hill is 40.5 m/s. How much work did the non-conservative forces do in going from thetop of the hill to the bottom of the hill? Given that the mass is 725 kg. (c) Include a sketch ofthe situation. [Diagram 2 pts.]

Step 1: Step 2: Step 3: Step 4:

Answered: If the roller coaster car at the top of…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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In the figure, a frictionless roller coaster car of mass m - 992 kg tops the first hill with speed vo- 11.9 m/s at heighth-47.0 m. How much work does the gravitational force do on the car from that point to (a) point A, (b) point B, and (c) point C? If the gravitational potential energy of the car-Earth system is taken to be zero at C, what is its value when the car is at (d) Band (e) A? First
A car with mass 1520 kg is traveling down the highway at a speed of 18 m/s when the driver slams on the brakes due to an accident up ahead. The car eventually comes to rest.According to the work-energy theorem the work is related to the change in kinetic energy, Wnet = Δ KE = KEfinal - KEinitial.(a) Using the work-energy relationship, determine how much net work is done on the car from the brakes? Report the magnitude of the the work (positive value) even though the work from brakes will be negative since the car is slowing down._____ J(b) The brakes apply a force of 24000 N to the car in order to make it stop. Using the fact that W = F d and the fact that the you found the work done (magnitude) by the brakes in part (b), determine the stopping distance, d, of the car.____ m
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A box slides down a ramp and work is done on the box by the forces of gravity and friction. Can the work of each of these forces be expressed in terms of the change in a potential-energy function? For each force explain why or why not.
In 1990,Walter Arfeulle of Beligium lifted a 281.5-kg object through a distance of 17.1 cm using only his teeth. (a) How much work was done on yhe object by Arfeuille in this lift,assuming the object was lifted at constant speed? (b)What total force was exerted on A rfeuille's teeth during the lift?
A car rounds a freeway exit turn of radius 40m at constant speed of 20m/s. The turn goes 3/4 around(not a full circle). How much work is done by the friction force on the car’s tires that allows it to turn?
a weight lifter holds a 50kg weight a distance of 3m above the ground for 30 seconds.How much work is done on the weight in that time? Calculate it both ways and make sure that they match.
During terrible weather at a ski-flying world championship, a ski jumper tried to adjust for bad conditions midway down the ramp but completely lost control and tumbled wildly off the side at its bottom into a scattering crowd. The 73-kg jumper left the ramp about 45 m lower than his starting position. After hitting the ground, the jumper crashed wildly and descended down the hill another 20 vertical meters before coming to rest. Here, friction cannot be ignored. Calculate the total work done on the ski jumper to bring him to rest. Round the final answer to the nearest whole number.
Matthew pushes a box of toys along a 5 m long ramp that is inclined 3 m high as shown in the figure below. The box has a total mass of 20 kg and the coefficient friction between the box and the ramp is 0.33. (a) How much force is needed by Matthew to move the box uniformly along the inclined ramp? (b) How much work is done by the force the box has travelled the 5.0 m length incline? (c) How much work is done by friction? (d) How much work is done by gravity? (e) How much work is done by the normal force? (f) What is the total work done by all the forces on the box?
Tom used 100N of force to drag a 10kgs of rocks up a 15 degree hill. There is an initial velocity of 1.5 m/s. The coefficient of kinetic friction is 0.40 and the rocks is dragged 7.5m. Find the work done in gravity? The work done by friction? The work done by Tom? The change in KE? The speed of the rocks after it is dragged 7.5m?
A crate of mass 9.80 kg is pulled horizontally by a force F = 116 N along an incline over a distance d = 4.94 m. The incline makes an angle of 20.3° with the horizontal. How much net work is done by both the gravitational force AND the pulling force F on the crate when it reaches the distance? (Consider the definition of work; Ignore fy shown} O 408 J O 299 J O 184 J O 588 J O 496 J O 330 J ook/ DO & 4. 6. 7. Y command command option
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