Good day to youJust curious of how it obtained the 77km/h in the solutions of the essential university physics volume one 4th edition by richard wolfson, not sure where it came from The question: A car moving at 90km/h negotiates a 110m radius banked turn designed for 60km/h what is the minimum co-efficient of friction needed for the car to stay on the road?Thanks in advance < Chapter 5, Problem 72PExplanation of SolutionWrite the equation for the maximum speed the car can have to stayon the road.v = VHsgrHere, v is the maximum speed the car can have to stay on the road,H, is the coefficient of static friction, g is the acceleration due togravity and ris the radius of the banked turn.Rewrite the above equation for u, .= HsgrgrConclusion:The value of g is 9.80 m/s² .It is given that the speed of the car is 77 km/h.Convert the speed 77 km/h into units of m/s.77 km/h = 77 km/h (1000 mI km60x60 s= 21.39 m/sSubstitute 21.39 m/s for v , 9.80 m/s² for g and 95 m for rin equation(I) to find µ, .(21.39 m/s)(9.80 m/s*)(95 m)= 0.49Therefore, the minimum coefficient of friction needed if the car isto stay on the road is 0.49.E Chapter 5. Problem 71PChapter 5. Problem 73P →

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Good day to you

Just curious of how it obtained the 77km/h in the solutions of the essential university physics volume one 4th edition by richard wolfson, not sure where it came from

The question: A car moving at 90km/h negotiates a 110m radius banked turn designed for 60km/h what is the minimum co-efficient of friction needed for the car to stay on the road?

Thanks in advance

< Chapter 5, Problem 72P
Explanation of Solution
Write the equation for the maximum speed the car can have to stay
on the road.
v = VHsgr
Here, v is the maximum speed the car can have to stay on the road,
H, is the coefficient of static friction, g is the acceleration due to
gravity and ris the radius of the banked turn.
Rewrite the above equation for u, .
= Hsgr
gr
Conclusion:
The value of g is 9.80 m/s² .
It is given that the speed of the car is 77 km/h.
Convert the speed 77 km/h into units of m/s.
77 km/h = 77 km/h (1000 m
I km
60x60 s
= 21.39 m/s
Substitute 21.39 m/s for v , 9.80 m/s² for g and 95 m for rin equation
(I) to find µ, .
(21.39 m/s)
(9.80 m/s*)(95 m)
= 0.49
Therefore, the minimum coefficient of friction needed if the car is
to stay on the road is 0.49.
E Chapter 5. Problem 71P
Chapter 5. Problem 73P →

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