MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Two blocks are connected by a light string that passes over a frictionless pulley as in the figure below. The system is released from rest while m, is on the floor and m, is a distance h above the floor. (a) Assuming m, > m, find an expression for the speed of m, just as it reaches the floor. (Use any variable or symbol stated above along with the following as necessary: g.) (b) Taking m, = 6.9 kg, m, = 3.9 kg, and h= 3,5 m, evaluate your answer to part (a). m/s (c) Find the speed of each block when m, has fallen a distance of 1.2 m. m/s
MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Two blocks are connected by a light string that passes over a frictionless pulley as in the figure below. The system is released from rest while m, is on the floor and m, is a distance h above the floor. (a) Assuming m, > m, find an expression for the speed of m, just as it reaches the floor. (Use any variable or symbol stated above along with the following as necessary: g.) (b) Taking m, = 6.9 kg, m, = 3.9 kg, and h= 3,5 m, evaluate your answer to part (a). m/s (c) Find the speed of each block when m, has fallen a distance of 1.2 m. m/s
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Expert Solution
Step 1
a) by work energy theorem on system
∆K = Wg + WT
(1/2)(m1+m2) vf2 - 0 = m1gh - m2gh + 0
vf2 = 2(m1 - m2)gh / (m1 + m2)
vf = √[2(m1 - m2)gh / (m1 + m2)]
b) vf = √[2(6.9-3.9)×9.8×3.5 / (6.9+3.9)]
vf = 4.36 m/s
c) at h = 1.2 m
vf = √[2(6.9-3.9)×9.8×1.2 / (6.9+3.9)]
vf = 2.55 m/s
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