Question in image 2) A car (m= 1a50 ks) going 7.0 mls.in an inelastiz collision. what speed does the massg Car (m= 900kg) the allidemve ff with afterwardsstr.kes aresting

Answered: =) A car (m= 1a50 kg) g° deion. what…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question in image

2) A car (m= 1a50 ks) going 7.0 mls.
in an inelastiz collision. what speed does the mass
g Car (m= 900kg) the allide
mve ff with afterwards
str.kes a
resting

Expert Solution

Step 1

The momentum of the system must be conserved in an inelastic collision. The momentum conservation gives,

$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2}) v$

Here, $m_{1}$ is the mass of the initially moving car, $v_{1}$ is the speed of the initially moving car before collision, $m_{2}$ is the mass of the car initially at rest, $v_{2}$ is the speed of the car initially at rest before the collision and v is the speed with which the cars move after the collision.

The value of $v_{2}$ is zero since the car is at rest. Thus,

$\begin{array}{rcl} m_{1} v_{1} + 0 & = & (m_{1} + m_{2}) v \\ v & = & \frac{m_{1} v_{1}}{m_{1} + m_{2}} \\ = & \frac{(1250 kg) (7.0 m/s)}{1250 kg + 900 kg} \\ = & 4.07 m/s \end{array}$

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