A proton moving through the coil to the left is deflected toward the bottom of the page. What is the direction of the current in the coil? Clockwise Counterclockwise

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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In this example, the magnetic field from a coil is
used to deflect an electron. The coil, which is being
used in an electron beam experiment, has 200 turns
and a radius of 13 cm. (a) What current is needed
to produce a magnetic field with a magnitude of
5.0 × 10-3 T at the center of the coil? (b)
(Figure 1) shows an electron being deflected as it
moves through the coil. What is the direction of
current in the coil?
Figure
B at center =
R
F
= 5.0 × 10-³ T
1 of 1
200 turns
SOLUTION
SET UP AND SOLVE Part (a): To find the needed current, we solve B =
=
Part A - Practice Problem:
Clockwise
=
Counterclockwise
Part (b): From the right-hand rule, with the velocity vector of the electron pointing to the left and the force vector pointing toward
the bottom of the page, the direction of the magnetic field must be out of the page. (Remember that we're dealing with a negative
charge.) The direction of the current must be counterclockwise.
Submit
μοΝΙ
2R
REFLECT The current required is directly proportional to the radius of the coil; the greater the distance from the center to the
conductor, the greater the current required. And the current required varies inversely with the number of turns; the more turns, the
smaller required current.
Request Answer
for I:
2RB
2(0.13 m) (5.0×10−³ T)
MoN (4πx10-7 T-m/A) (200 turns)
A proton moving through the coil to the left is deflected toward the bottom of the page. What is the direction of the current in
the coil?
P Pearson
5.2 A
Constants
Transcribed Image Text:In this example, the magnetic field from a coil is used to deflect an electron. The coil, which is being used in an electron beam experiment, has 200 turns and a radius of 13 cm. (a) What current is needed to produce a magnetic field with a magnitude of 5.0 × 10-3 T at the center of the coil? (b) (Figure 1) shows an electron being deflected as it moves through the coil. What is the direction of current in the coil? Figure B at center = R F = 5.0 × 10-³ T 1 of 1 200 turns SOLUTION SET UP AND SOLVE Part (a): To find the needed current, we solve B = = Part A - Practice Problem: Clockwise = Counterclockwise Part (b): From the right-hand rule, with the velocity vector of the electron pointing to the left and the force vector pointing toward the bottom of the page, the direction of the magnetic field must be out of the page. (Remember that we're dealing with a negative charge.) The direction of the current must be counterclockwise. Submit μοΝΙ 2R REFLECT The current required is directly proportional to the radius of the coil; the greater the distance from the center to the conductor, the greater the current required. And the current required varies inversely with the number of turns; the more turns, the smaller required current. Request Answer for I: 2RB 2(0.13 m) (5.0×10−³ T) MoN (4πx10-7 T-m/A) (200 turns) A proton moving through the coil to the left is deflected toward the bottom of the page. What is the direction of the current in the coil? P Pearson 5.2 A Constants
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