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A car is stuck in the mud. A tow truck puls on the car with the arrangement shown in the figure below. The tow cable is under a tension of of 2,620 N and puls downward and to the left on the pie its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut; that is, each is a bar whose weight is small compared to the forces it eerts and wt exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as follows. Make a ge as to which way (pushing or pulling) each force acts on the top pin. Draw a free-body diagram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equat From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. A negative answer means the direction should reversed, but the absolute value correctly gives the magnitude of the force. Ifa strut puls on a pin, it is in tension. If it pushes, the strut is in compression. Identify whether each strut is in tensie in compression. (Assume e, 62° and e, 48.) force exerted by strut A N Select. force exerted by strut B N Select

A car is stuck in the mud. A tow truck puls on the car with the arrangement shown in the figure below. The tow cable is under a tension of of 2,620 N and puls downward and to the left on the pie its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut; that is, each is a bar whose weight is small compared to the forces it eerts and wt exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as follows. Make a ge as to which way (pushing or pulling) each force acts on the top pin. Draw a free-body diagram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equat From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. A negative answer means the direction should reversed, but the absolute value correctly gives the magnitude of the force. Ifa strut puls on a pin, it is in tension. If it pushes, the strut is in compression. Identify whether each strut is in tensie in compression. (Assume e, 62° and e, 48.) force exerted by strut A N Select. force exerted by strut B N Select

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A car is stuck in the mud. A tow truck puls on the car with the arrangement shown in the figure below. The tow cable is under a tension of of 2,620 N and pulis downward and to the left on the pin at its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut; that is, each is a bar whose weight is small compared to the forces it exerts and which exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as followrs. Make a guess as to which way (pushing or pulling) each force acts on the top pin. Draw a free-body diegram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equations. From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. A negative answer means the direction should be reversed, but the absolute value correctly gives the magnitude of the force. Ifa strut puls on a pin, it is in tension. If it pushes, the strut is in compression. Identify whether each strut is in tension or in compression. (Assume ,- 62° and ,- 48) force exerted by strut A N Select force exerted by strut B N Select
Transcribed Image Text:A car is stuck in the mud. A tow truck puls on the car with the arrangement shown in the figure below. The tow cable is under a tension of of 2,620 N and pulis downward and to the left on the pin at its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut; that is, each is a bar whose weight is small compared to the forces it exerts and which exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as followrs. Make a guess as to which way (pushing or pulling) each force acts on the top pin. Draw a free-body diegram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equations. From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. A negative answer means the direction should be reversed, but the absolute value correctly gives the magnitude of the force. Ifa strut puls on a pin, it is in tension. If it pushes, the strut is in compression. Identify whether each strut is in tension or in compression. (Assume ,- 62° and ,- 48) force exerted by strut A N Select force exerted by strut B N Select
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